Question

我抓取一个字符串并使用$ .parseJSON（字符串），但一直收到以下错误：

uncaught exception: Invalid JSON: {"0":{"chartHtml":"&lt;p&gt; Slide 1&lt;/p&gt; ","presNote":"","chartOrderIndex":0},"1":{"chartHtml":"&lt;p&gt; Slide 2&lt;/p&gt; ","presNote":"","chartOrderIndex":1},"2":{"chartOrderIndex":2},"3":{"chartHtml":"&lt;p&gt; e 3&lt;/p&gt; ","presNote":"","chartOrderIndex":3},"4":{"chartHtml":"&lt;p&gt; Slide 4&lt;/p&gt; ","presNote":"","chartOrderIndex":4},"5":{"chartHtml":"&lt;p&gt; Slide 5&lt;/p&gt; ","presNote":"","chartOrderIndex":5},"6":{"chartOrderIndex":6}}

运行slideJson.d后调试期间的Firebug结果：

    >>> slideJson.d
"{"0":{"chartHtml":"&lt;p&gt; Slide 1&lt;/p&gt; ","presNote":"","chartOrderIndex":0},"1":{"chartHtml":"&lt;p&gt; Slide 2&lt;/p&gt; ","presNote":"","chartOrderIndex":1},"2":{"chartOrderIndex":2},"3":{"chartHtml":"&lt;p&gt; e 3&lt;/p&gt; ","presNote":"","chartOrderIndex":3},"4":{"chartHtml":"&lt;p&gt; Slide 4&lt;/p&gt; ","presNote":"","chartOrderIndex":4},"5":{"chartHtml":"&lt;p&gt; Slide 5&lt;/p&gt; ","presNote":"","chartOrderIndex":5},"6":{"chartOrderIndex":6}}"

以下是对json进行反序列化的一些调用：

function (slideJson) {
var slideObj, jsonStr;
if (slideJson.d) {
    slideObj = $.parseJSON(slideJson.d);

Ajax调用以获取具有内容类型的Json：

$.ajax({
    url: 'Someurl',
    type: "POST",
    data: "{}",
    dataType: "json",
    contentType: "application/json; charset=utf-8",
    success: function (data) { somenamespace.loadSlides(data); }
});

Answer 1

您的JSON有效，请查看http://jsonlint.com/

您的内容类型如何？如果您使用的是PHP，请设置以下标题：

header('Content-type: application/json');

Answer 2

有问题的JSON字符串最终在\n属性中包含\r和chartHTML，默认情况下由CKeditor .getData()方法生成。因为我从萤火虫那里粘贴错误，所以它们不可见，JSON似乎是有效的，这导致了我的困惑。

感谢那些回答。

Answer 3

你不必使用$.parseJSON它是形象很好的。尝试直接使用它。

工作demo

无效的JSON但json看起来有效

3 个答案: