Question

如何在以下查询中对结果进行分组：

SELECT (
             SELECT SUM(wky) FROM table
             WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16'
            ) +
            (SELECT SUM(earnings) FROM table
            WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16') / .75

以上查询返回所有网站的wky +（收益/ .75）（每个网站都有不同日期的wky和收益编号。在上述查询中，我将在哪里放一个组？我希望我的结果是按site_id分组，因为上述查询只返回所有这些收入的总和。

谢谢！

Answer 1

SELECT site_id, (SUM(wky) + (SUM(earnings) / 0.75)) 
FROM Earnings_Date
WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16'
GROUP BY site_id

您的数据来自两个查询的同一个表，因此您可以将它们组合在一起。

Answer 2

SELECT (
         SELECT SUM(wky) FROM table
         WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16'
        ) +
        (SELECT SUM(earnings) FROM table
        WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16') / .75

, site_id GROUP BY site_id

：）

MySQL：分组结果

2 个答案: