Question

我试图复制Alex Kuhl在他的优秀帖子中给出的例子：http://kuhlit.blogspot.com/2011/04/ajax-file-uploads-and-csrf-in-django-13.html

然而，我在复制这个方面并不太成功。

####### upload_page.html  

{% extends "base.html" %}
{% load i18n %}
{% block title %}Blog Post: Upload Files.{% endblock %}

{% block content %} 
<div id="maintext"> 
<p>To upload a file, click on the button below.</p>
<div id="file-uploader">
<noscript>
<p>Please enable JavaScript to use file uploader.</p>
<!-- or put a simple form for upload here -->
</noscript>
</div>
<script>
    function createUploader(){
    var uploader = new qq.FileUploader( {
        action: "{% url ajax_upload %}",
        element: $('#file-uploader')[0],
        multiple: false,
        onComplete: function( id, fileName, responseJSON ) {
          if( responseJSON.success )
        alert( "success!" ) ;
          else
        alert( "Sorry, your upload has failed! Please contact us by telephone or email." ) ;
        },
        onAllComplete: function( uploads ) {
          // uploads is an array of maps
          // the maps look like this: { file: FileObject, response: JSONServerResponse }
          alert( "All complete!" ) ;
        },
        params: {
          'csrf_token': '{{ csrf_token }}',
          'csrf_name': 'csrfmiddlewaretoken',
          'csrf_xname': 'X-CSRFToken',
        },
      } ) ;
    }

    // in your app create uploader as soon as the DOM is ready
    // don't wait for the window to load
    window.onload = createUploader;
</script>
</div>
{% endblock %}

views.py如下：

############### views.py
def upload_page( request ):
    ctx = RequestContext( request, {
        'csrf_token': get_token( request ),
    })
    return render_to_response( 'success/upload_page.html', ctx )

def save_upload( uploaded, filename, raw_data ):
    filename = settings.UPLOAD_STORAGE_DIR
    '''
    raw_data: if True, uploaded is an HttpRequest object with the file being
        the raw post data
        if False, uploaded has been submitted via the basic form
        submission and is a regular Django UploadedFile in request.FILES
    '''
    try:
        from io import FileIO, BufferedWriter
        with BufferedWriter( FileIO( filename, "wb" ) ) as dest:
            # if the "advanced" upload, read directly from the HTTP request
            # with the Django 1.3 functionality
            if raw_data:
                foo = uploaded.read( 1024 )
                while foo:
                    dest.write( foo )
                    foo = uploaded.read( 1024 )
            # if not raw, it was a form upload so read in the normal Django chunks fashion
            else:
                for c in uploaded.chunks( ):
                    dest.write( c )
            # got through saving the upload, report success
            return True
    except IOError:
        # could not open the file most likely
        pass
        return False

def ajax_upload( request ):
    if request.method == "POST":   
        if request.is_ajax( ):
            # the file is stored raw in the request
            upload = request
            is_raw = True
            # AJAX Upload will pass the filename in the querystring if it is the "advanced" ajax upload
            try:
                filename = request.GET[ 'qqfile' ]
            except KeyError:
                return HttpResponseBadRequest( "AJAX request not valid" )
        # not an ajax upload, so it was the "basic" iframe version with submission via form
        else:
            is_raw = False
            if len( request.FILES ) == 1:
                upload = request.FILES.values( )[ 0 ]
            else:
                raise Http404( "Bad Upload" )
            filename = upload.name

        # save the file
        success = save_upload( upload, filename, is_raw )

        # let Ajax Upload know whether we saved it or not
        import json
        ret_json = { 'success': success, }
        return HttpResponse( json.dumps( ret_json ) )

urls.py如下：

####### urls.py

urlpatterns = patterns('',
(r'media/(?P<path>.*)$', 'django.views.static.serve', {'document_root':   settings.MEDIA_ROOT}),
(r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}),
url(r'^$', index,name='home'),
url( r'^ajax_upload$', ajax_upload, name="ajax_upload" ),
url( r'^upload/$', upload_page, name="upload_page" ),
(r'^admin/', include(admin.site.urls)),
(r'^accounts/', include('regfields.urls')),

# Examples:
# url(r'^$', 'mysite.views.home', name='home'),
# url(r'^mysite/', include('mysite.foo.urls')),

# Uncomment the admin/doc line below to enable admin documentation:
# url(r'^admin/doc/', include('django.contrib.admindocs.urls')),

# Uncomment the next line to enable the admin:
# url(r'^admin/', include(admin.site.urls)),

代码也在：http://dpaste.com/600444/

虽然一切都很好，但上传总是失败。

我使用：filename = settings.UPLOAD_STORAGE_DIR，其中，UPLOAD_STORAGE_DIR在settings.py中被定义为'/ media /'

有没有人可以指出我哪里出错了（对不起，我是网络编程的新手，之前从未使用过JS，但可以合理地在python中编程！）

Answer 1

您的Javascript中存在拼写错误。它应该是{% csrf_token %}而不是{{ csrf_token }}。

修改在您发表评论之后，我仔细查看了您链接的文章。

您需要包含库fileuploader.js。它将使用带有正确事件处理程序的表单替换id为file-uploader的占位符div。用纯HTML创建表单是行不通的。

我建议您查看Github存储库中的示例：https://github.com/alexkuhl/file-uploader/tree/master/client

Answer 2

您需要将return True添加到if语句中，以检查它是否为原始数据，否则即使上传成功也会返回False：

...
if raw_data:
    foo = uploaded.read(1024)
    while foo:
        dest.write(foo)
        foo = uploaded.read(1024) 
    return True
...

django ajax / jquery文件上传

2 个答案: