Question

我需要在关联数组中搜索和替换。

例如：

$user = "user1"; // I've updated this

$myarray = array("user1" => "search1", "user2" => "search2", "user3" => "search1" ) ;

我想替换search1 search4。我怎样才能做到这一点？

更新：我忘了提到数组有几个search1值，我只想更改key is == $user的值。很抱歉没有提到这个。

Answer 1

$myarray = array("user1" => "search1", "user2" => "search2" );

foreach($myarray as $key => $val)
{
    if ($val == 'search1') $myarray[$key] = 'search4';
}

Answer 2

有一个功能：array_map()。

// Using a lamba function, PHP 5.3 required
$newarray = array_map(
    function($v) { if ($v == 'search1') $v = 'search4'; return $v; },
    $myarray
);

如果您不想使用lambda函数，请定义一个普通函数或方法并回调它。

Answer 3

$user = "user1";
$myarray = array("user1" => "search1", "user2" => "search2", "user3" => "search1" );
foreach($myarray as $key => $val)
{
    if ($val == 'search1' and $key == $user )
    {
       $myarray[$key] = 'search4';
       break;
    }
}
print_r($myarray);

打印：

Array
(
    [user1] => search4
    [user2] => search2
    [user3] => search1
)

Answer 4

为什么不做呢

if (isset($myarray[$user])) $myarray[$user] = 'search4';

Answer 5

$originalArray = array( "user1" => "search1" , "user2" => "search2" );
$pattern = 'search1';
$replace = 'search4';

$replacedArray = preg_replace( '/'.$pattern.'/' , $replace , $originalArray );

修复评论中提到的风险，以回应this solution

Answer 6

更新

由于帖子更新了，我有机会睡觉，我意识到我的回答是愚蠢的。如果你有一个给定的键，你需要改变它的值，为什么要遍历整个数组呢？

$user    = 'user1';
$search  = 'search1';
$replace = 'search4';
$array   = array('user1' => 'search1', 'user2' => 'search2');

if (isset($array[$user]) && $search === $array[$user]) $array[$user] = $replace;

与@ Joseph的方法类似（几乎相同），但有一些调整：

$user = 'user1';
$array = array("user1" => "search1", "user2" => "search2" );

foreach($array as $key => &$value) {
    if ($key === $user) {
        $value = 'search4';
        break; // Stop iterating after key has been found
    }
}

通过引用传递是在foreach内编辑的更好方法，可以说更快。

Answer 7

在关联数组或数字内搜索和替换替换任何关联数组中的值，数组可以是任何深度

function array_value_replace($maybe_array, $replace_from, $replace_to) {

    if (!empty($maybe_array)) {
        if (is_array($maybe_array)) {
            foreach ($maybe_array as $key => $value) {
                $maybe_array[$key] = array_value_replace($value, $replace_from, $replace_to);
            }
        } else {
            if(is_string($maybe_array)){
                $maybe_array = str_replace($replace_from, $replace_to, $maybe_array);
            }               
        }
    }

    return $maybe_array;
}

Answer 8

如果您想要特定的密钥，那么您只需添加以前的ans中的密钥条件。

$user = "user1";
$myarray = array("user1" => "search1", "user2" => "search2" );

foreach($myarray as $key => $val)
{
    if ($val == 'search1' && $key == $user) $myarray[$key] = 'search4';
}

Answer 9

使用str_replace应该可以工作：

$myarray = array("user1" => "search1", "user2" => "search2" ) ;

$newArray = str_replace('search1', 'search4', $myarray);

Answer 10

继Joseph的回答后，使用preg_replace可以让您在其他情况下使用该代码：

function pregReplaceInArray($pattern,$replacement,$array) {
    foreach ($array as $key => $value) {
        $array[$key] = preg_replace($pattern,$replacement,$value);
    }   
    return $array;
}

在关联数组中搜索和替换

10 个答案:

更新