Question

我有三个表：用户，角色，授权

用户

|username|lastName|firstName|....
|dan     |foo     |dan
|russ    |bar     |russ

角色

|role                 |roleLevel
|ROLE_ADMIN           | 0
|ROLE_COMPANY_ADMIN   | 20
|ROLE_MARKETING_ADMIN | 50
|ROLE_SERVICE_ADMIN   | 80
|ROLE_USER            | 100

当局

|username|authority
|dan     |ROLE_SERVICE_ADMIN  |
|dan     |ROLE_USER           |
|russ    |ROLE_MARKETING_ADMIN|
|russ    |ROLE_ADMIN          |
|russ    |ROLE_COMPANY_ADMIN  |

我需要让所有DISTINCT用户的roleLevel高于我传入的INT及其最低的roleLevel

我现在拥有的是：

SELECT DISTINCT u.username, u.firstName, u.lastName, r.roleLevel FROM AUTHORITIES a, ROLES r, USERS u
WHERE r.role =  a.authority
AND a.username = u.username 
AND r.roleLevel >= #{roleLevel} 
ORDER BY u.lastName, u.firstName

但是这为多个角色的用户提供了多行。如何让角色级别低于我传入的用户？

Answer 1

假设用户可以有多行，您需要确定如何显示角色。

SELECT DISTINCT u.username, u.firstName, u.lastName, 
    max(r.roleLevel) largestRoleLevel,
    min(r.roleLevel) minimumRoleLevel,
    GROUP_CONCAT(r.roleLevel SEPARATOR ', ') allRoleLevels
FROM USERS u
INNER JOIN AUTHORITIES a ON a.username = u.username
INNER JOIN ROLES r ON r.role = a.authority

WHERE r.roleLevel >= #{roleLevel} 
GROUP BY u.username, u.firstname, u.lastname
ORDER BY u.lastName, u.firstName

Answer 2

它为您提供了多行，因为您没有指定您想要最低的行;加上你使用了大于而不是低于。

SELECT u.username, u.firstName, u.lastName, min(r.roleLevel) minroleLevel
  FROM AUTHORITIES a, ROLES r, USERS u
 WHERE r.role =  a.authority
   AND a.username = u.username 
   AND r.roleLevel <= #{roleLevel}
 GROUP BY u.username, u.firstName, u.lastName 
 ORDER BY u.lastName, u.firstName

Answer 3

SELECT 
    u.username, u.firstName, u.lastName, 
    min(r.roleLevel) minRoleLevel
FROM 
    authorities a 
    JOIN roles r ON r.role = a.authority
    JOIN users u ON u.username = a.username
GROUP BY 
    u.username, u.firstName, u.lastName 
HAVING 
    minRoleLevel >= #{roleLevel}
ORDER BY 
    u.lastName, u.firstName

MySql和Mybatis选择不同的行，其值为＆lt; = ##

3 个答案: