Question

我正在尝试解析以下内容：

[{"Student":{"student_id":"19","student_name":"Test"},"Teacher":{"teacher_id":"1"}}]

但我不确定获取值19，Test和1的语法，请帮助。

Answer 1

尝试，

var test = '[{"Student":{"student_id":"19","student_name":"Test"},"Teacher":{"teacher_id":"1"}}]'; 

var obj = jQuery.parseJSON(test);

console.log(obj[0].Teacher.teacher_id)

http://jsfiddle.net/ZsUrN/

Answer 2

在PHP中：

$json = '[{"Student":{"student_id":"19","student_name":"Test"},"Teacher":{"teacher_id":"1"}}]
';

$data = json_decode($json);

// You can access values like this:
$student = $data[0]->Student;
$student_id = $student->student_id;
$student_name = $student->student_name;
$teacher_id = $data[0]->Teacher->teacher_id;

在Javascript中：

var json =  '[{"Student":{"student_id":"19","student_name":"Test"},"Teacher":{"teacher_id":"1"}}]
';

var data;
if (window.JSON) {
    data = JSON.parse(json);
} else {
    data = eval(json);
}

// You can access values like this:

var student = data[0].Student;
var student_id = student.student_id;
var student_name = sudent.student_name;
var teatcher_id = data[0].Teacher.teacher_id;

Answer 3

var persons = JSON.parse('[{"Student":{"student_id":"19","student_name":"Test"},"Teacher":{"teacher_id":"1"}}]');
var myStudentID = persons[0].Student.student_id;
var myStudentTest = persons[0].Student.Test;
var myTeacherID = persons[0].Teacher.teacher_id;

_{_{_{我觉得这是家庭作业}}}

需要parseJSON的语法

3 个答案: