我似乎无法弄清楚为什么我不断收到这个错误的输出。
输入文件:
ff1
ff2
ff3
ff10
ff11
ff20
ff21
ff23
gb20
gb10
gh23
输出文件:
FF01
FF02
FF03
FF010
FF011
FF020
FF021
FF023
GB020
GB010
GH023
代码:
import os
import sys
#directory is the directory we will work from
directory = "C:\\Users\\user\\Desktop"
os.chdir(directory)
renameWhat = ["ff", "gb", "gh"]
oldFile = open("New Text Document.txt")
buffer = oldFile.read()
for item in renameWhat:
for i in range(0, 50):
if i < 10:
buffer = buffer.replace(item + str(i), item.upper() + "0" + str(i))
else:
buffer = buffer.replace(item + str(i), item.upper() + str(i))
outFile = open("test.txt", "w")
outFile.write(buffer)
outFile.close()
oldFile.close()
需要做什么:
我正在尝试将ff替换为大写(完成),然后我需要为所有less than or equal to 9
的数字添加零。所以我认为if i is less than 10
应该足够好;但这并不是因为它为9以上的所有内容添加了零。我尝试使用len(str(i))
来确保它只是长度为1,但仍然无效;我错过了什么?
答案 0 :(得分:3)
原始解决方案不起作用的原因是它没有检查它是否匹配整行/字/数字。因此,例如在用ff1
替换FF01
之后,您的缓冲区就是:
FF01
ff2
ff3
FF010
FF011
ff20
ff21
ff23
gb20
gb10
gh23
答案 1 :(得分:2)
这是一个简单的解决方案:
with open("New Text Document.txt") as oldFile:
with open("test.txt", "w") as outFile:
for line in oldFile:
start, end = line[:2], line[2:]
outfile.write(start.upper() + end.strip().zfill(2) + '\n')
如果您只想大写特定前缀:
with open("New Text Document.txt") as oldFile:
with open("test.txt", "w") as outFile:
for line in oldFile:
start, end = line[:2], line[2:]
if start in renameWhat:
start = start.upper()
outfile.write(start + end.strip().zfill(2) + '\n')
答案 2 :(得分:1)
只需使用zfill string method:
>>> str(1).zfill(2)
'01'
>>> str(10).zfill(2)
'10'
答案 3 :(得分:0)
import re
a = """ff1
ff2
ff3
ff10
ff11
ff20
ff21
ff23
gb20
gb10
gh23
"""
regex = re.compile('([a-zA-Z]*)([0-9]*)\n')
b = ""
for i in regex.findall(a):
if i[0] in ['ff','gb','gh']:
b+=i[0].upper()
else:
b+=i[0]
if int(i[1]) < 10:
b+= "0"
b+= i[1]+"\n"
print b
结果:
FF01
FF02
FF03
FF10
FF11
FF20
FF21
FF23
GB20
GB10
GH23