让PHP脚本计算MySQL结果？

Question

我有一个网页，使用以下代码列出每个特定日期的结果。

  $day_events = "SELECT * FROM tbl_events WHERE day='".$day_id."'";
  $events_result = mysql_query($day_events);
  while($event_row=mysql_fetch_array($events_result)) {
  $calendar.= "<span>".$event_row['event']."</span>";
  }

如何编辑此内容以列出在...

中找到的事件数量

SELECT * FROM tbl_events WHERE day='".$day_id."'

...查询？

Answer 1

SELECT count(*) FROM tbl_events WHERE day ...

顺便说一句，您只需使用上一次查询中的mysql_num_rows()即可。

Answer 2

$day_events = "SELECT COUNT(*) FROM tbl_events WHERE day='".$day_id."'";
print mysql_result(mysql_query($day_events),0)

Answer 3

echo mysql_num_rows($evenets_result);

寻找这个？

Answer 4

$events_count = mysql_num_rows(mysql_query($day_events));