如何在SQL Server 2005中删除列的IDENTITY属性

时间:2009-04-03 13:42:20

标签: sql sql-server-2005 tsql

我希望能够将带有标识列的表中的数据插入到SQL Server 2005中的临时表中。

TSQL类似于:

-- Create empty temp table
SELECT *
INTO #Tmp_MyTable
FROM MyTable
WHERE 1=0
...
WHILE ...
BEGIN
    ...
    INSERT INTO #Tmp_MyTable
    SELECT TOP (@n) *
    FROM MyTable
    ...

END

上面的代码使用标识列创建了#Tmp_Table,然后插入失败并显示错误“只有在使用列列表且IDENTITY_INSERT为ON时,才能指定表'#Tmp_MyTable'中标识列的显式值。“

TSQL中有没有办法在临时表中删除列的标识属性而不明确列出所有列?我特别想使用“SELECT *”,这样如果将新列添加到MyTable,代码将继续有效。

我相信删除并重新创建列会改变它的位置,因此无法使用SELECT *。

更新

我尝试在一个响应中建议使用IDENTITY_INSERT。它不起作用 - 见下面的repro。我做错了什么?

-- Create test table
CREATE TABLE [dbo].[TestTable](
    [ID] [numeric](18, 0) IDENTITY(1,1) NOT NULL,
    [Name] [varchar](50) NULL,
 CONSTRAINT [PK_TestTable] PRIMARY KEY CLUSTERED 
(
    [ID] ASC
)
) 
GO
-- Insert some data
INSERT INTO TestTable
(Name)
SELECT 'One'
UNION ALL
SELECT 'Two'
UNION ALL
SELECT 'Three'
GO
-- Create empty temp table
SELECT *
INTO #Tmp
FROM TestTable
WHERE 1=0

SET IDENTITY_INSERT #Tmp ON -- I also tried OFF / ON
INSERT INTO #Tmp
SELECT TOP 1 * FROM TestTable

SET IDENTITY_INSERT #Tmp OFF 
GO
-- Drop test table
DROP TABLE [dbo].[TestTable]
GO

请注意,错误消息“表'#TmpMyTable'中标识列的显式值只能在使用列列表时指定且IDENTITY_INSERT为ON。” - 我特别不想使用如上所述的列列表。

更新2 试过the suggestion from Mike,但这也给出了同样的错误:

-- Create empty temp table
SELECT *
INTO #Tmp
FROM (SELECT
      m1.*
      FROM TestTable                 m1
          LEFT OUTER JOIN TestTable  m2 ON m1.ID=m2.ID
      WHERE 1=0
 ) dt

INSERT INTO #Tmp
SELECT TOP 1 * FROM TestTable

至于为什么我要这样做:MyTable是一个临时表,可以包含大量要合并到另一个表中的行。我想处理登台表中的行,插入/更新我的主表,并在每个事务处理N行的循环中从登台表中删除它们。我意识到还有其他方法可以实现这一目标。

更新3

我无法使Mike's solution工作,但它建议使用以下解决方案:使用非标识列作为前缀并删除标识列:

SELECT CAST(1 AS NUMERIC(18,0)) AS ID2, *
INTO #Tmp
FROM TestTable
WHERE 1=0
ALTER TABLE #Tmp DROP COLUMN ID

INSERT INTO #Tmp
SELECT TOP 1 * FROM TestTable

迈克建议只在临时表中存储密钥也是一个很好的建议,但在这种特殊情况下,有理由我希望在临时表中包含所有列。

5 个答案:

答案 0 :(得分:7)

你可以尝试

SET IDENTITY_INSERT #Tmp_MyTable ON 
-- ... do stuff
SET IDENTITY_INSERT #Tmp_MyTable OFF

即使它有标识列,也可以选择#Tmp_MyTable

不会工作:

-- Create empty temp table
SELECT *
INTO #Tmp_MyTable
FROM MyTable
WHERE 1=0
...
WHILE ...
BEGIN
    ...
    SET IDENTITY_INSERT #Tmp_MyTable ON 

    INSERT INTO #Tmp_MyTable
    SELECT TOP (@n) *
    FROM MyTable

    SET IDENTITY_INSERT #Tmp_MyTable OFF 
    ...    
END

(导致错误“只有在使用列列表并且IDENTITY_INSERT为ON时才能指定表'#Tmp'中标识列的显式值。”)

似乎没有办法实际删除列 - 但这会改变OP提到的列的顺序。丑陋的黑客:根据#Tmp_MyTable ...

创建一个新表

我建议您编写一个存储过程,该存储过程基于具有相同列(按顺序)的表名(MyTable)创建临时表,但缺少标识属性。

您可以使用以下代码:

select t.name as tablename, typ.name as typename, c.*
from sys.columns c inner join
     sys.tables t on c.object_id = t.[object_id] inner join
     sys.types typ on c.system_type_id = typ.system_type_id
order by t.name, c.column_id

了解反射在TSQL中的工作原理。我相信你必须循环遍历相关表的列并执行动态(手工制作,存储在字符串中然后评估)alter语句到生成的表。

你介意为世界其他地方发布这样的存储过程吗?这个问题在其他论坛中似乎也出现了很多......

答案 1 :(得分:3)

如果您只是按照描述处理行,那么将前N个主键值选择到临时表中会不会更好:

CREATE TABLE #KeysToProcess
(
     TempID    int  not null primary key identity(1,1)
    ,YourKey1  int  not null
    ,YourKey2  int  not null
)

INSERT INTO #KeysToProcess (YourKey1,YourKey2)
SELECT TOP n YourKey1,YourKey2  FROM MyTable

密钥不应经常更改(我希望),但其他列可以这样做无害。

获取插入的@@ ROWCOUNT,你可以在TempID上轻松循环,从1到@@ ROWCOUNT

和/或

只需将#KeysToProcess加入您的MyKeys表即可,无需复制所有数据。

这在我的SQL Server 2005上运行正常,其中MyTable.MyKey是一个标识列。

-- Create empty temp table
SELECT *
INTO #TmpMikeMike
FROM (SELECT
      m1.*
      FROM MyTable                 m1
          LEFT OUTER JOIN MyTable  m2 ON m1.MyKey=m2.MyKey
      WHERE 1=0
 ) dt

INSERT INTO #TmpMike
SELECT TOP 1 * FROM MyTable

SELECT * from #TmpMike



修改
这个工作,没有错误......

-- Create empty temp table
SELECT *
INTO #Tmp_MyTable
FROM (SELECT
          m1.*
          FROM MyTable                 m1
              LEFT OUTER JOIN MyTable  m2 ON m1.KeyValue=m2.KeyValue
          WHERE 1=0
     ) dt
...
WHILE ...
BEGIN
    ...
    INSERT INTO #Tmp_MyTable
    SELECT TOP (@n) *
    FROM MyTable
    ...

END

但是,你真正的问题是什么?为什么在将“*”插入此临时表时需要循环?您可以改变策略并提出更好的算法。

答案 2 :(得分:1)

编辑按照Daren的建议切换IDENTITY_INSERT肯定是更优雅的方法,在我的情况下我需要删除标识列,以便我可以将所选数据重新插入到源表中

我解决这个问题的方法就是像你一样创建临时表,显式删除标识列,然后动态构建sql,以便我有一个排除标识列的列列表(如你的情况那样)如果模式有变化,proc仍然可以工作)然后在这里执行sql是一个样本

declare @ret int
Select * into #sometemp from sometable
Where
id = @SomeVariable

Alter Table #sometemp Drop column SomeIdentity 

Select @SelectList = ''
Select @SelectList = @SelectList 
+ Coalesce( '[' + Column_name + ']' + ', ' ,'')
from information_schema.columns
where table_name = 'sometable'
and Column_Name <> 'SomeIdentity'

Set @SelectList = 'Insert into sometable (' 
+ Left(@SelectList, Len(@SelectList) -1) + ')'
Set @SelectList = @SelectList 
+ ' Select * from #sometemp '
exec @ret  =  sp_executesql  @selectlist

答案 3 :(得分:0)

我已经编写了这个程序,作为自动和快速删除列标识的许多答案的汇编:

CREATE PROCEDURE dbo.sp_drop_table_identity @tableName VARCHAR(256) AS
BEGIN
    DECLARE @sql VARCHAR (4096);
    DECLARE @sqlTableConstraints VARCHAR (4096);
    DECLARE @tmpTableName VARCHAR(256) = @tableName + '_noident_temp';

    BEGIN TRANSACTION

    -- 1) Create temporary table with edentical structure except identity
    -- Idea borrowed from https://stackoverflow.com/questions/21547/in-sql-server-how-do-i-generate-a-create-table-statement-for-a-given-table
    -- modified to ommit Identity and honor all constraints, not primary key only!
    SELECT
        @sql = 'CREATE TABLE [' + so.name + '_noident_temp] (' + o.list + ')'
        + ' ' + j.list
    FROM sysobjects so
    CROSS APPLY (
        SELECT
            ' [' + column_name + '] '
            + data_type
            + CASE data_type
                WHEN 'sql_variant' THEN ''
                WHEN 'text' THEN ''
                WHEN 'ntext' THEN ''
                WHEN 'xml' THEN ''
                WHEN 'decimal' THEN '(' + CAST(numeric_precision as VARCHAR) + ', ' + CAST(numeric_scale as VARCHAR) + ')'
                ELSE COALESCE('(' + CASE WHEN character_maximum_length = -1 THEN 'MAX' ELSE CAST(character_maximum_length as VARCHAR) END + ')', '')
            END
            + ' '
            /* + case when exists ( -- Identity skip
            select id from syscolumns
            where object_name(id)=so.name
            and name=column_name
            and columnproperty(id,name,'IsIdentity') = 1
            ) then
            'IDENTITY(' +
            cast(ident_seed(so.name) as varchar) + ',' +
            cast(ident_incr(so.name) as varchar) + ')'
            else ''
            end + ' ' */
            + CASE WHEN IS_NULLABLE = 'No' THEN 'NOT ' ELSE '' END
            + 'NULL'
            + CASE WHEN information_schema.columns.column_default IS NOT NULL THEN ' DEFAULT ' + information_schema.columns.column_default ELSE '' END
            + ','
        FROM
            INFORMATION_SCHEMA.COLUMNS
        WHERE table_name = so.name
        ORDER BY ordinal_position
        FOR XML PATH('')
    ) o (list)
    CROSS APPLY(
        SELECT
            CHAR(10) + 'ALTER TABLE ' + @tableName + '_noident_temp ADD ' + LEFT(alt, LEN(alt)-1)
        FROM(
            SELECT
                CHAR(10)
                + ' CONSTRAINT ' + tc.constraint_name  + '_ni ' + tc.constraint_type + ' (' + LEFT(c.list, LEN(c.list)-1) + ')'
                + COALESCE(CHAR(10) + r.list, ', ')
            FROM
                information_schema.table_constraints tc
                CROSS APPLY(
                    SELECT
                        '[' + kcu.column_name + '], '
                    FROM
                        information_schema.key_column_usage kcu
                    WHERE
                        kcu.constraint_name = tc.constraint_name
                    ORDER BY
                        kcu.ordinal_position
                    FOR XML PATH('')
                ) c (list)
                OUTER APPLY(
                    -- https://stackoverflow.com/questions/3907879/sql-server-howto-get-foreign-key-reference-from-information-schema
                    SELECT
                        '  REFERENCES [' + kcu1.constraint_schema + '].' + '[' + kcu2.table_name + ']' + '([' + kcu2.column_name + ']) '
                        + CHAR(10)
                        + '    ON DELETE ' + rc.delete_rule
                        + CHAR(10)
                        + '    ON UPDATE ' + rc.update_rule + ', '
                    FROM information_schema.referential_constraints as rc
                        JOIN information_schema.key_column_usage as kcu1 ON (kcu1.constraint_catalog = rc.constraint_catalog AND kcu1.constraint_schema = rc.constraint_schema AND kcu1.constraint_name = rc.constraint_name)
                        JOIN information_schema.key_column_usage as kcu2 ON (kcu2.constraint_catalog = rc.unique_constraint_catalog AND kcu2.constraint_schema = rc.unique_constraint_schema AND kcu2.constraint_name = rc.unique_constraint_name AND kcu2.ordinal_position = KCU1.ordinal_position)
                    WHERE
                        kcu1.constraint_catalog = tc.constraint_catalog AND kcu1.constraint_schema = tc.constraint_schema AND kcu1.constraint_name = tc.constraint_name
                ) r (list)
            WHERE tc.table_name = @tableName
            FOR XML PATH('')
        ) a (alt)
    ) j (list)
    WHERE
        xtype = 'U'
    AND name NOT IN ('dtproperties')
    AND so.name = @tableName

    SELECT @sql as '1) @sql';
    EXECUTE(@sql);

    -- 2) Obtain current back references on our table from others to reenable it later
    -- https://stackoverflow.com/questions/3907879/sql-server-howto-get-foreign-key-reference-from-information-schema
    SELECT
        @sqlTableConstraints = (
            SELECT
                'ALTER TABLE [' + kcu1.constraint_schema + '].' + '[' + kcu1.table_name + ']'
                + ' ADD CONSTRAINT ' + kcu1.constraint_name + '_ni FOREIGN KEY ([' + kcu1.column_name + '])'
                + CHAR(10)
                + '  REFERENCES ['  + kcu2.table_schema + '].[' + kcu2.table_name + ']([' + kcu2.column_name + '])'
                + CHAR(10)
                + '    ON DELETE ' + rc.delete_rule
                + CHAR(10)
                + '    ON UPDATE ' + rc.update_rule + ' '
            FROM information_schema.referential_constraints as rc
                JOIN information_schema.key_column_usage as kcu1 ON (kcu1.constraint_catalog = rc.constraint_catalog AND kcu1.constraint_schema = rc.constraint_schema AND kcu1.constraint_name = rc.constraint_name)
                JOIN information_schema.key_column_usage as kcu2 ON (kcu2.constraint_catalog = rc.unique_constraint_catalog AND kcu2.constraint_schema = rc.unique_constraint_schema AND kcu2.constraint_name = rc.unique_constraint_name AND kcu2.ordinal_position = KCU1.ordinal_position)
            WHERE
                kcu2.table_name = 'department'
            FOR XML PATH('')
        );
    SELECT @sqlTableConstraints as '8) @sqlTableConstraints';
    -- Execute at end

    -- 3) Drop outer references for switch (structure must be identical: http://msdn.microsoft.com/en-gb/library/ms191160.aspx) and rename table
    SELECT
        @sql = (
            SELECT
                ' ALTER TABLE [' + kcu1.constraint_schema + '].' + '[' + kcu1.table_name + '] DROP CONSTRAINT ' + kcu1.constraint_name
            FROM information_schema.referential_constraints as rc
                JOIN information_schema.key_column_usage as kcu1 ON (kcu1.constraint_catalog = rc.constraint_catalog AND kcu1.constraint_schema = rc.constraint_schema AND kcu1.constraint_name = rc.constraint_name)
                JOIN information_schema.key_column_usage as kcu2 ON (kcu2.constraint_catalog = rc.unique_constraint_catalog AND kcu2.constraint_schema = rc.unique_constraint_schema AND kcu2.constraint_name = rc.unique_constraint_name AND kcu2.ordinal_position = KCU1.ordinal_position)
            WHERE
                kcu2.table_name = @tableName
            FOR XML PATH('')
        );
    SELECT @sql as '3) @sql'
    EXECUTE (@sql);

    -- 4) Switch partition
    -- http://www.calsql.com/2012/05/removing-identity-property-taking-more.html
    SET @sql = 'ALTER TABLE ' + @tableName + ' switch partition 1 to ' + @tmpTableName;
    SELECT @sql as '4) @sql';
    EXECUTE(@sql);

    -- 5) Rename real old table to bak
    SET @sql = 'EXEC sp_rename ' + @tableName + ', ' + @tableName + '_bak';
    SELECT @sql as '5) @sql';
    EXECUTE(@sql);

    -- 6) Rename temp table to real
    SET @sql = 'EXEC sp_rename ' + @tmpTableName + ', ' + @tableName;
    SELECT @sql as '6) @sql';
    EXECUTE(@sql);

    -- 7) Drop bak table
    SET @sql = 'DROP TABLE ' + @tableName + '_bak';
    SELECT @sql as '7) @sql';
    EXECUTE(@sql);

    -- 8) Create again doped early constraints
    SELECT @sqlTableConstraints as '8) @sqlTableConstraints';
    EXECUTE(@sqlTableConstraints);


    -- It still may fail if there references from objects with WITH CHECKOPTION
    -- it may be recreated - https://stackoverflow.com/questions/1540988/sql-2005-force-table-rename-that-has-dependencies
    COMMIT
END

使用非常简单:

EXEC sp_drop_table_identity @tableName = 'some_very_big_table'

利益和限制:

  1. 它使用switch partition(适用于非分区表格)语句快速移动而没有完整数据副本。它还适用于适用性的一些条件。
  2. 它在没有身份的飞行表副本上制作。这样的解决方案I also post separately,它也可能需要调整不那么简单的结构,如复合字段(它满足我的需求)。
  3. 如果表包含在由CHECKOUPTION(sp,views)绑定的模式的对象中,则会阻止切换(请参阅代码中的最后一条注释)。可以另外编写脚本以暂时删除这种绑定。我还没有那样做。
  4. 欢迎所有反馈。

答案 4 :(得分:0)

在SQL Server上删除标识列(特别是对于大型数据库)的最有效方法是直接修改DDL元数据,在早于2005的SQL Server上可以使用以下命令:

sp_configure 'allow update', 1
go
reconfigure with override
go

update syscolumns set colstat = 0 --turn off bit 1 which indicates identity column
where id = object_id('table_name') and name = 'column_name'
go

exec sp_configure 'allow update', 0
go
reconfigure with override
go

SQL Server 2005+不支持使用override 进行重新配置,但是当SQL Server实例以单用户模式启动时,您可以执行Ad Hoc查询(使用 -m启动数据库实例) 标志,即“C:\ Program Files \ Microsoft SQL Server \ MSSQL10.MSSQLSERVER \ MSSQL \ Binn \ sqlservr.exe -m”,确保以管理员身份运行,带有专用管理控制台(来自SQL Management Studio connect)使用 ADMIN:前缀,即ADMIN:MyDatabase)。列metdata存储在 sys.sysschobjs 内部表中(未显示DAC):

use myDatabase

update sys.syscolpars set status = 1, idtval = null -- status=1 - primary key, idtval=null - remove identity data
where id = object_id('table_name') AND name = 'column_name' 

有关此方法的更多信息on this blog