PHP如何创建所有任务的列表

Question

好的，我有一个任务表，这个表有一个外键，即“projectID”

我选择该表中具有相同projectID的所有行。但我现在想要在列表中输出结果（“<li></li>”）

//Select tasks
$sql = "SELECT * FROM tasks WHERE projectID = '".$project_ID."'";
$result5 = $db->sql_query($sql);
$data5 = mysql_fetch_assoc($result5);

Answer 1

您将需要遍历每一行并输出taskList列值：

$sql = "SELECT * FROM tasks WHERE projectID = '".$project_ID."'";
$result5 = $db->sql_query($sql);

$data5 = mysql_fetch_assoc($result5);
// this will let you handle an empty result set without a count.
if( $data5 )
{
    // opening the list only if there are things to put there
    echo "<ul >";
    do
    {
        // output the value from one row.
        echo "<li>" . $data5['taskName'].'</li>';
    }while($data5 = mysql_fetch_assoc($result5));
    echo "</ul>";
}
else
{ 
    echo 'No tasks found!';
}