- (void)tableView:(UITableView *)tableView
didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
NSArray *listData =[self.tableContents objectForKey:
[self.sortedKeys objectAtIndex:[indexPath section]]];
NSUInteger row = [indexPath row];
NSString *rowValue = [listData objectAtIndex:row];
NSString *message = [[NSString alloc] initWithFormat:rowValue];
UIAlertView *alert = [[UIAlertView alloc]
initWithTitle:@"You Better Be There Or Be Watching It!"
message:message delegate:nil
cancelButtonTitle:@"Go Knights!"
otherButtonTitles:nil];
[alert show];
[alert release];
[message release];
[tableView deselectRowAtIndexPath:indexPath animated:YES];
}
Line of code that throws error:
NSString *message = [[NSString alloc] initWithFormat:rowValue];
----------
Warning Message: format not a string literal and no format arguments
答案 0 :(得分:0)
stringWithFormat:
方法采用带n
个参数的字符串格式。根据您的需要,只需使用:
NSString *message = rowValue;
根据您的代码示例,您不需要为字符串对象分配内存或提供某种格式。