在我之前的问题Search for range Latitude/Longitude coordinates我的解决方案是创建下表。
mysql> select * from spatial_table where MBRContains(GeomFromText('LINESTRING(9 9, 11 11)'), my_spots);
+------+---------------------------------+
| id | my_spots | my_polygons |
+------+-------------+-------------------+
| 1 | $@ $@ $@ $@ |
+------+-------------+-------------------+
现在我需要将下表中的现有lat / lng对转换并移动到spatial_table。我将如何构建我的查询以实现此目的?我目前正在使用以下查询来插入。
mysql> insert into spatial_table values (1, GeomFromText('POINT(1 1)'), GeomFromText('POLYGON((1 1, 2 2, 0 2, 1 1))'));
Query OK, 1 row affected (0.00 sec)
mysql> insert into spatial_table values (1, GeomFromText('POINT(10 10)'), GeomFromText('POLYGON((10 10, 20 20, 0 20, 10 10))') );
Query OK, 1 row affected (0.00 sec)
现有表格:
+-------------+---------+--------+-----------+----- ------+-------------+--------------+
| location_id | country | region | city | latitude | longitude | name |
+=============|=========|========|===========|============|=============|==============|
| 316625 | US | CA | Santa Cruz| 37.044799 | -122.102096 | Rio Theatre |
+-------------+---------+--------+-----------+------------+-------------+--------------+
答案 0 :(得分:8)
这是成功的秘诀:) 我原来的表:
mysql> describe gls;
+-------------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-------------+--------------+------+-----+---------+-------+
| location_id | int(255) | NO | PRI | 0 | |
| country | varchar(255) | NO | | | |
| region | varchar(255) | NO | | | |
| city | varchar(255) | NO | | | |
| latitude | float(13,10) | NO | | | |
| longitude | float(13,10) | NO | | | |
+-------------+--------------+------+-----+---------+-------+
8 rows in set (0.00 sec)
第1步:添加新的POINT列
mysql> alter table gls add my_point point;
Query OK, 247748 rows affected (4.77 sec)
Records: 247748 Duplicates: 0 Warnings: 0
步骤2:使用lat / lng字段中的值更新my_point。
UPDATE gls SET my_point = PointFromText(CONCAT('POINT(',gls.longitude,' ',gls.latitude,')'));
第3步:检查
mysql> select aswkt(my_point) from gls where city='Santa Cruz';
+--------------------------------------+
| aswkt(my_point) |
+--------------------------------------+
| POINT(-122.1020965576 37.0447998047) |
| POINT(-66.25 -12.2833003998) |
| POINT(-2.3499999046 42.6666984558) |
+--------------------------------------+
答案 1 :(得分:2)
假设你有一张这样的表:
mysql> select * from spatial_table;
+------+---------------------------+-----------------------------------------------------------------------------------+---------+--------+
| id | my_spots | my_polygons | lon | lat |
+------+---------------------------+-----------------------------------------------------------------------------------+---------+--------+
| 1 | ?? ?? | ?? ?? @ @ @ ?? ?? | -122.11 | -37.11 |
| 1 | $@ $@ | $@ $@ 4@ 4@ 4@ $@ $@ | -122.11 | -37.11 |
+------+---------------------------+-----------------------------------------------------------------------------------+---------+--------+
2 rows in set (0.00 sec)
如果要创建具有lon lat值的几何列(仅作为点,对于其他类型的几何,语法略有不同),您可以这样做:
mysql> alter table spatial_table add column (go_slugs geometry);
这是几何类型,如果它是所有单个位置,则可以使列类型为point
。然后只需更新新列:
mysql> update spatial_table set go_slugs = point(lon, lat);
使用aswkt函数获取人类可读数据以确认这是正确的:
mysql> select aswkt(go_slugs) from spatial_table;
+-----------------------------------------------+
| aswkt(go_slugs) |
+-----------------------------------------------+
| POINT(-122.11000061035156 -37.11000061035156) |
| POINT(-122.11000061035156 -37.11000061035156) |
| POINT(-123.4000015258789 37.79999923706055) |
+-----------------------------------------------+
3 rows in set (0.00 sec)