Question

如何摆脱json处理的下方括号？

[{"success":true,"filename":"bialding_and_rebialding_plymouth02.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth03.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth04.jpg"}]

上面的结果由下面的类处理成一个数组，

function handle_upload($upload_directory)
    {
        # Loop the code according to the number of files.
        for($i = 1; $i <= $this->total; $i++)
        {
            ...

            if ($this->file->save($upload_directory.$name_filtered.'.'.$file_extension , $i-1))
            {
                $message[] = array('success'=>true,'filename'=>$name_filtered.'.'.$file_extension);
            }
            else 
            {
                $message[] = array('error'=> 'Could not save uploaded file.' . 'The upload was cancelled, or server error encountered');
            }
        }

        return $message;
    }

然后我使用json_encode将数组转换为json格式，

$uploader = new uploader();
$result = $uploader->handle_upload('uploads/');

echo htmlspecialchars(json_encode($result), ENT_NOQUOTES);

但我只在没有括号的结果中需要这个，

{"success":true,"filename":"bialding_and_rebialding_plymouth02.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth03.jpg"},{"success":true,"filename":"bialding_and_rebialding_plymouth04.jpg"}

Answer 1

str_replace(array('[', ']'), '', htmlspecialchars(json_encode($result), ENT_NOQUOTES));？

Answer 2

你可以通过在你的函数中执行以下操作来拉出json并返回它：

return $message[0];  //  only json

或者您可以将其全部归还，然后将其删除：

$uploader = new uploader();
$result1 = $uploader->handle_upload('uploads/');
$result2 = $result[0];

删除json中的括号？

2 个答案: