<form method="post" action="" id="infoform">
<label for="first">
First Name</label>
<input type="text" name="first" id="first" class="field validate[required]">
</br>
<label for="surname">
Last Name</label>
<input type="text" name="surname" id="surname" class="field validate[required]"> </br>
<label for="email">
Email</label>
<input type="text" name="email" id="email" class=" field email validate[required,custom[email]]">
</br>
<div class="radios">
<input id="test2" checked="checked" type="radio" name="message" value="register" />
Register for Updates</input>
<input id="test1" type="radio" name="message" value="msgs" />
Send a Message</input>
</div>
<div class="msg">
<label for="message" id="messagelabel">
Message</label>
<textarea type="text" name="message" id="message"></textarea>
</div>
<input id="submit" type="submit" value=""><div class="test3">
<a class="sbmt">Register</a></div>
<div class="test4">
<a class="sbmt">Send</a></div>
</input>
</form>
如果选中单选框'test1',则会出现div msg。然后通过ajax将其发送到电子邮件php脚本:
<?php
$EmailTo = "matt@explosivetitles.com";
$adminSubject = "Civitas Message";
$firstName = Trim(stripslashes($_POST['first']));
$Surname = Trim(stripslashes($_POST['surname']));
$Email = Trim(stripslashes($_POST['email']));
$Message = Trim(stripslashes($_POST['message']));
$adminheaders = 'From: "Civitas website" <info@civitas.com>';
$adminBody .= "First Name: ";
$adminBody .= $firstName;
$adminBody .= "\n";
$adminBody .= "Surname: ";
$adminBody .= $Surname;
$adminBody .= "\n";
$adminBody .= "Email: ";
$adminBody .= $Email;
$adminBody .= "\n";
$adminBody .= "Message: ";
$adminBody .= $Message;
$adminBody .= "\n";
$adminMail = mail($EmailTo, $adminSubject, $adminBody, $adminheaders);
if ($adminMail){
echo "true";
}
else{
echo "false";
}
?>
但是,如果显示消息框,我只希望发送电子邮件的“消息”部分。我怎么能这样做?
答案 0 :(得分:0)
你可以这样做:
$adminBody .= "First Name: ";
$adminBody .= $firstName;
$adminBody .= "\n";
$adminBody .= "Surname: ";
$adminBody .= $Surname;
$adminBody .= "\n";
$adminBody .= "Email: ";
$adminBody .= $Email;
$adminBody .= "\n";
if (isset($_POST['message'])) {
$adminBody .= "Message: ";
$adminBody .= $Message;
}
$adminBody .= "\n";
isset()
将检查变量是否存在,如果是,则返回true
。
答案 1 :(得分:0)
PHP不会查看元素的id
,相反,当发送POST
或GET
方法时,它会查看name
属性。在您编写的代码中,您有两个输入元素textarea
和radio input
具有相同的名称“message”。当两者都被发送时,$_POST
变量变成一个数组,并使用name
属性作为提交值的索引,并且PHP数组不能有重复的索引,因此要解决这个问题,重命名一个。对于radio input
,我建议将name
属性设置为type
。
<?php
$send = "matt@explosivetitles.com";
$subject = "Civitas Message";
$details = array (
"first" => @$_POST["first"],
"surname" => @$_POST["surname"],
"email" => @$_POST["email"],
"message" => @$_POST["message"]
);
foreach ($details as $index => $value) {
$details[$index] = trim ( stripslashes ($value));
}
if (@$_POST["type"] == "register") {
// Whatever happens when they select "register"
} else if (@$_POST["type"] == "msgs") {
$header = "From 'Civitas website' <info@civitas.com>";
$body = $details["first"] . " " . $details["surname"] . " "
. "<" . $details["email"] . ">"
. "Message: \n"
. $details["message"];
$mail = mail ($send, $subject, $body, $header);
if ($mail) {
return true;
} else {
return false;
}
}
?>
另外,你的代码伤害了我的眼睛,所以我重写了它。