Question

我有三个表都加入到一个表中。这是代码：

class App < ActiveRecord::Base
  has_many :app_servers
  has_many :servers, :through => :app_servers
  has_many :environments, :through => :app_servers
end

class Server < ActiveRecord::Base
  has_many :app_servers
  has_many :apps, :through => :app_servers
  has_many :environments, :through => :app_servers
end

class Environment < ActiveRecord::Base
  has_many :app_servers
  has_many :apps, :through => :app_servers
  has_many :servers, :through => :app_servers
end

class AppServer < ActiveRecord::Base
  belongs_to :app
  belongs_to :server
  belongs_to :environment
end

我已经在app和Server模型中使用了scaffold并且可以访问它们，但是当我为AppServer创建一个脚手架并尝试访问索引页面时，它给了我这个错误：

No route matches {:action=>"show", :controller=>"app_servers", :id=>#<AppServer app_id: 3, server_id: 1, environment_id: 2>}

我认为错误的原因是因为当我创建AppServer表时，我指定了:id => false。

所以我真正想要做的就是拥有创建页面，然后允许我将当前保存的服务器映射到当前保存的应用程序到特定环境。关于如何克服这个问题的任何想法？

另外，我的连接模型没有ID是错误的，因为它最初是has_and_belongs_to_many模型？

提前致谢

修改以下是index.html.erb文件：

<h1>Listing app_servers</h1>

<table>
  <tr>
    <th></th>
    <th></th>
    <th></th>
  </tr>

<% @app_servers.each do |app_server| %>
  <tr>
<td><%= app_server%></td>
    <td><%= link_to 'Show', app_server %></td>
    <td><%= link_to 'Edit', edit_app_server_path(app_server) %></td>
<td><%= link_to 'Destroy', app_server, :confirm => 'Are you sure?', :method => :delete %></td>
  </tr>
<% end %>
</table>

<br />

<%= link_to 'New App server', new_app_server_path %>

还有app_servers_controller.rb文件：

class AppServersController < ApplicationController
  # GET /app_servers
  # GET /app_servers.xml
  def index
    @app_servers =AppServer.all

    respond_to do |format|
      format.html # index.html.erb
      format.xml  { render :xml => @app_servers }
    end
  end

  # GET /app_servers/1
  # GET /app_servers/1.xml
  def show
    @app_server = AppServer.find(params[:id])

    respond_to do |format|
      format.html # show.html.erb
      format.xml  { render :xml => @app_server }
    end
  end

  # GET /app_servers/new
  # GET /app_servers/new.xml
  def new
    @app_server = AppServer.new

    respond_to do |format|
      format.html # new.html.erb
      format.xml  { render :xml => @app_server }
    end
  end

  # GET /app_servers/1/edit
  def edit
    @app_server = AppServer.find(params[:id])
  end

  # POST /app_servers
  # POST /app_servers.xml
  def create
    @app_server = AppServer.new(params[:app_server])

    respond_to do |format|
      if @app_server.save
        format.html { redirect_to(@app_server, :notice => 'App server was successfully     created.') }
        format.xml  { render :xml => @app_server, :status => :created, :location =>     @app_server }
      else
    format.html { render :action => "new" }
        format.xml  { render :xml => @app_server.errors, :status =>     :unprocessable_entity }
      end
    end
  end

  # PUT /app_servers/1
  # PUT /app_servers/1.xml
  def update
    @app_server = AppServer.find(params[:id])

    respond_to do |format|
      if @app_server.update_attributes(params[:app_server])
        format.html { redirect_to(@app_server, :notice => 'App server was successfully updated.') }
        format.xml  { head :ok }
      else
        format.html { render :action => "edit" }
        format.xml  { render :xml => @app_server.errors, :status => :unprocessable_entity }
      end
    end
  end

  # DELETE /app_servers/1
  # DELETE /app_servers/1.xml
  def destroy
    @app_server = AppServer.find(params[:id])
    @app_server.destroy

    respond_to do |format|
      format.html { redirect_to(app_servers_url) }
      format.xml  { head :ok }
    end
  end
end

Answer 1

确定。这里最简单的解决方案是返回id。或者你应该重写一些标准路线，如

get '/app_servers/show', :to => "app_servers#show", :as => :app_server

并从控制器中删除id提取。

我的意思是 - 返回IDS - 这很容易

<强> UPD

这里快速而肮脏的解决方案是将AppServer模型添加到这个小方法：

def to_param
  "#{environment_it}_#{app_id}_#{server_id}"
end

试图访问没有ID的连接表

1 个答案: