Question

假设我有下表：

mysql> CREATE TABLE example (
    -> `id` INT(10) NOT NULL PRIMARY KEY AUTO_INCREMENT,
    -> `stuff` VARCHAR(255) NOT NULL
    -> );
Query OK, 0 rows affected (0.06 sec)

stuff列已声明为NOT NULL。当在预准备语句中将null值传递给它时，它自然会失败。因此：

mysql> PREPARE test FROM "INSERT INTO example (stuff) VALUES (?)";
Query OK, 0 rows affected (0.00 sec)
Statement prepared

mysql> SET @a = NULL;
Query OK, 0 rows affected (0.00 sec)

mysql> EXECUTE test USING @a;
ERROR 1048 (23000): Column 'stuff' cannot be null

错误消息Column 'stuff' cannot be null非常清楚。但是当我使用PDO的绑定参数执行完全相同的查询时，它不会给我错误消息。这是一个示例脚本：

<?php

$host = 'localhost';

$user = 'fakeuser';
$pass = 'fakepass';
$db_name = 'fakedb';

$dsn = "mysql:host=$host;port=3306;dbname=$db_name";

// Connect to the database.
try {
    $DB = new PDO(
        $dsn,
        $user,
        $pass,
        array(PDO::ATTR_PERSISTENT => true)
    );
} catch (PDOException $e) {
    print "Unable to connect to database.\n";
    exit;
}

// Make sure everything is handled in the UTF-8 character set.
$DB->exec('SET NAMES UTF8');

$SQL = 'INSERT INTO example (stuff) VALUES (:stuff)';

$query = $DB->prepare($SQL);

$values = array(
    ':stuff' => null,
);

$saved = $query->execute($values);

print "\$saved is:\n";
var_dump($saved);
print "\n\n";

print "Error code is:\n";
var_dump($DB->errorCode());
print "\n\n";

print "Error info is:";
var_dump($DB->errorInfo());
print "\n\n";

其中输出以下内容：

$ php test.php

$saved is:
bool(false)

Error code is:
string(5) "00000"

Error info is:array(3) {
  [0]=>
  string(5) "00000"
  [1]=>
  NULL
  [2]=>
  NULL
}

通过PHP回复给我的调试信息都不是很有用。我怎样才能让它给我真正的错误信息而不是这个00000垃圾？

Answer 1

请尝试$query->errorInfo()。

如何使用PDO预处理语句从MySQL中获取有意义的错误消息？

1 个答案: