目前,我有几个Twitter提要的json数据,我解析它来填充我的列表。我有一个对象,“图像”,其中包含我想要在列表中设置为ImageView的用户图标的URL。我无法弄清楚如何获取网址并在Imageview中为每一行加载图片。这是代码:
public void getTweets(String selection) {
String formatedcat = selection.toLowerCase();
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
JSONObject json = JSONfunctions
.getJSONfromURL("http://example.com/tweet.php");
try {
JSONArray category = json.getJSONArray(formatedcat);
for (int i = 0; i < category.length(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
JSONObject c = category.getJSONObject(i);
map.put("id", String.valueOf(i));
map.put("name",
c.getString("fullName") + "\n(#" + c.getString("name")
+ ") ");
map.put("text",
c.getString("text") + "\n - "
+ c.getString("timestamp"));
mylist.add(map);
}
} catch (JSONException e) {
Log.e("log_tag", "Error parsing data " + e.toString());
}
ListAdapter adapter = new SimpleAdapter(this, mylist, R.layout.list,
new String[] { "name", "text"}, new int[] { R.id.item_title,
R.id.item_subtitle});
setListAdapter(adapter);
final ListView lv = getListView();
lv.setTextFilterEnabled(true);
}
答案 0 :(得分:0)
How to display image from URL on Android
看到这个问题。看起来对我很实用。在getView()
方法中显示图像,填充列表并实例化子视图。