Question

以下是我们的目标：

我们希望为特定用户选择每月和每个月获得的收入。

以下是我们的表格

产品，购买，用户，月份

用户1 .. *产品，产品1 .. *购买

产品的列为“user_id”，购买时有一列'product_id'

months只是一个表格，每个月都包含一个字符串。目前，我们正在使用它来执行一些左连接，如下所示。

SELECT months.name, IFNULL(sum(purchase.price), 0) as revenue
FROM months
    LEFT JOIN purchase
        ON DATE_FORMAT(purchase.purchase_date, '%M') = months.name
        AND DATE_FORMAT(purchase_date, '%Y') = DATE_FORMAT(CURRENT_DATE, '%Y')
        AND purchase.status = 2
GROUP BY name
ORDER BY months.id ASC;

这对所有用户和本月所有购买都有效（购买状态为2表示完成）。下一部分是如何根据用户ID过滤这个？表'product'具有我们正在寻找的user_id，表购买具有'product_id'。每当我尝试某些东西时，它既不会做任何事情，也不会删除所有我们不想要的空值。

ATTEMPT @NathanialWools where子句将删除收入为零的所有行（或者因为IFNULL语句而为null）。这就是我试过的：

SELECT name, IFNULL(sum(purchase.price), 0) as revenue
FROM months
    LEFT JOIN purchase
        ON DATE_FORMAT(purchase.purchase_date, '%M') = months.name
        AND DATE_FORMAT(purchase_date, '%Y') = DATE_FORMAT(CURRENT_DATE, '%Y')
        AND purchase.status = 2
    LEFT JOIN product
        ON product.id = purchase.product_id
WHERE product.user_id = 1
GROUP BY name
ORDER BY months.id ASC;

Answer 1

如果您有可以从中开始的用户列表，请加入到几个月，然后加入产品。（如果你不只是从产品开始）。

SELECT u.user_id, m.name, IFNULL(sum(p.price), 0) as revenue 
FROM user u
CROSS JOIN months m
LEFT JOIN product d
    ON u.user_id = d.user_id
LEFT JOIN purchase p
    ON DATE_FORMAT(p.purchase_date, '%M') = m.name
    AND DATE_FORMAT(p.purchase_date, '%Y') = DATE_FORMAT(CURRENT_DATE, '%Y')
    AND p.product_id = d.product_id
    AND p.status = 2
WHERE u.user_id = <user you care about>
GROUP BY u.user_id, m.name
ORDER BY m.id ASC;

Answer 2

LEFT JOIN on product，并添加一个WHERE子句，其中user_id为null或user_id等于您的值。

Answer 3

你尝试了什么？

SELECT months.name, u.user_id, sum(IFNULL(purchase.price, 0)) as revenue
FROM months
    LEFT JOIN purchase pu
        ON DATE_FORMAT(purchase.purchase_date, '%M') = months.name
        AND DATE_FORMAT(purchase_date, '%Y') = DATE_FORMAT(CURRENT_DATE, '%Y')
        AND purchase.status = 2
    LEFT JOIN product pr
        ON pr.product_id = pr.product_id
    LEFT JOIN user u
        ON u.user_id = pr.user_id
GROUP BY pu.name, u.user_id
ORDER BY months.id ASC;

Answer 4

内部选择似乎可以做到这一点。单独购买的左连接不足以过滤。以下是适用于我的解决方案：

SELECT m.name, IFNULL(sum(b.price), 0) as revenue
FROM months as m
LEFT JOIN (SELECT price, purchase_date, status
           FROM purchase, product
           WHERE purchase.product_id = product.id
           AND product.user_id = 1) as b
    ON DATE_FORMAT(b.purchase_date, '%M') = m.name
    AND DATE_FORMAT(b.purchase_date, '%Y') = DATE_FORMAT(CURRENT_TIMESTAMP, '%Y')
    AND status = 2
GROUP BY m.name
ORDER BY m.id ASC

根据您想要查看的用户，显然会更改“1”。

感谢大家的投入，使调试更快。

图表数据的SQL查询帮助

4 个答案: