Question

我正试图让json数组的内部对象（我的行话可能不正确）看起来像这样：

{
"News": {
    "0": {
        "name": "nytimes",
        "fullName": "The New York Times",
        "text": "@OwenPerry We heard from the owner of the house and corrected the article http://t.co/8GEgGy7",
        "timestamp": "2011-08-15 12:20:36"
    },
    "1": {
        "name": "HuffingtonPost",
        "fullName": "Huffington Post",
        "text": "Look out! New Zealand Skier chased by angry bulls - http://t.co/L0PZkx4",
        "timestamp": "2011-08-15 12:19:04"
    }
}
}

我检索内部对象的代码如下所示：

        JSONArray category = json.getJSONArray("News");
        JSONArray innerobj = category.getJSONArray(0);
        for (int i = 0; i < innerobj.length(); i++) {
            HashMap<String, String> map = new HashMap<String, String>();
            JSONObject c = innerobj.getJSONObject(i);

            map.put("id", String.valueOf(i));
            map.put("name", c.getString("fullName") + "\n(#"
                    + c.getString("name") + ") ");
            map.put("text",
                    c.getString("text") + "\n - "
                            + c.getString("timestamp"));
            mylist.add(map);
        }

关于我做错了什么的想法？

Answer 1

您没有JSONArray，而是JSONObjects。您的JSONObject结构是：

主JSONObject，其中包含1 JSONObject - “新闻”
“news”包含两个JSONObjects，“0”和“1”
每个对象都有四个字段 - “name”，“fullname”，“text”和“timestamp”

考虑：

JSONObject jobj = new JSONObject(yourString);
JSONObject newsobj = jobj.getJSONObject("news");
JSONObject firstOne = newsobj.getJSONObject("0"); // this is the object "0"
....

Android：Json获取内部对象

1 个答案: