Question

这是可重复的，可能是一个错误。在这个例子中，我有三个表：

付款
paymentID
日期
paymentType

信用卡
paymentID
cardNo
cardTypeID

CardType
ID
说明

付款和贷记分别是父表和子类表。代码如下：

payment.cfc

component persistent="true" table="payment" discriminatorcolumn="paymentType"{
    property name="paymentID";  
    property name="date";
}

credit.cfc

component persistent="true" extends="payment" joincolumn="paymentID"  
    table="credit" discriminatorvalue="ccard"{
    property name="cardNo";  
    property name="cardTypes" fieldtype="many-to-one" lazy="true" cfc="cardType"
        fkcolumn="cardTypeID";
}

cardType.cfc

component persistent="true" table="cardType"{
    property name="id";
    property name="description";
    property name="creditCards" fieldtype="one-to-many" lazy="extra" 
        type="struct" structkeycolumn="id" cfc="credit" fkcolumn="cardType";
}

错误在于与cardType.cfc的“一对多”关系。当ORM生成SQL时，它会尝试将fkcolumn应用于父类的select和where子句：

select
    creditcard0_.cardType as cardType30569_1_,
    creditcard0_.PaymentID as PaymentID1_,
    creditcard0_.PaymentID as PaymentID30570_0_,
    creditcard0_.Date as Date30570_0_,
    creditcard0_1_.cardNo as cardNo30572_0_,
    creditcard0_1_.cardType as cardType30572_0_ 
from
    Payment creditcard0_ 
inner join
    CreditCardPayment creditcard0_1_ 
      on creditcard0_.PaymentID=creditcard0_1_.PaymentID 
where
    creditcard0_.cardType=?

当调用简单的entityload（“cardType”）时，这会导致很多“CardType不存在”错误。

任何人都知道为什么它不能正确地应用于子类，并且它可能是我缺少的配置设置。

提前致谢。

Answer 1

所以，如果我像这样映射hbmxml文件，显然它解决了这个问题：

<map lazy="extra" name="creditCards" table="CreditCardPayment" inverse="true">
    <key column="cardType"/>
    <map-key column="CardNo" type="string"/>
    <many-to-many unique="true" column="PaymentID" class="cfc:entities.credit"/>
</map>

Answer 2

尝试将mapedSuperClass =“true”添加到付款CFC。不确定这是否会像通常那样使用mappedSuperClass用于非持久性“基础”对象。

映射到子类时，ColdFusion ORM关系映射“一对多”问题

2 个答案: