Question

当我的Sentry客户端尝试记录错误时，我收到以下错误：

 Unable to reach Sentry log server: HTTP Error 400: BAD REQUEST (url: http://localhost:8000/sentry/store/, body: Missing data)
       Traceback (most recent call last):
         File "/home/deploy/env/lib/python2.6/site-packages/sentry/client/base.py", line 210, in send
           return self.send_remote(url=url, data=message, headers=headers)
         File "/home/deploy/env/lib/python2.6/site-packages/sentry/client/base.py", line 194, in send_remote
           response = urllib2.urlopen(req, data).read()
         File "/usr/lib/python2.6/urllib2.py", line 126, in urlopen
           return _opener.open(url, data, timeout)
         File "/usr/lib/python2.6/urllib2.py", line 397, in open
           response = meth(req, response)
         File "/usr/lib/python2.6/urllib2.py", line 510, in http_response
           'http', request, response, code, msg, hdrs)
         File "/usr/lib/python2.6/urllib2.py", line 435, in error
           return self._call_chain(*args)
         File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain
           result = func(*args)
         File "/usr/lib/python2.6/urllib2.py", line 518, in http_error_default
           raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
       HTTPError: HTTP Error 400: BAD REQUEST Http 404

它尝试记录的错误不会保存到服务器。

谢谢！

Answer 1

我也有这个问题。

查看了哨兵代码库并找到了它抛出400的位置（web/views.py的第424行）

它发生在检查标头HTTP_AUTHORIZATION的else子句中。为了让这个通过，我不得不将WSGIPassAuthorization On添加到我的apache conf ....

我认为我上面提到的else子句必须有一个bug，因为这应该被处理....

无法到达Sentry Log Server错误400

1 个答案: