从xml反序列化对象会出错:'内存流不可扩展'

时间:2011-08-16 19:14:59

标签: c# serialization

我重新使用了一些旧的代码(我认为是较旧的.net版本),用于从xml反序列化一个对象(最后我将粘贴用于序列化对象的代码)

这是代码:

/// <summary>
        /// Reconstruct an object from an XML string
        /// </summary>
        /// <param name="xml"></param>
        /// <returns></returns>
        public static T DeserializeObject<T>(string xml)
        {
            using (MemoryStream stream = new MemoryStream(StringToUTF8ByteArray(xml)))
            using (new XmlTextWriter(stream, Encoding.UTF8))
            {
                return (T)new XmlSerializer(typeof(T)).Deserialize(stream);
            }
        }

它给了我这个错误:'Memory stream is not expandable'在返回行。

出了什么问题?

这是序列化代码:

MemoryStream stream = new MemoryStream();
            using (XmlTextWriter xml = new XmlTextWriter(stream, Encoding.UTF8))
            {
                XmlSerializer xs = new XmlSerializer(item.GetType());
                xs.Serialize(xml, item);
                stream = (MemoryStream)xml.BaseStream;
            }

            return UTF8ByteArrayToString(stream.ToArray());

修改

这是缺失的功能

private static Byte[] StringToUTF8ByteArray(string pXmlString)
        {
            UTF8Encoding encoding = new UTF8Encoding();
            byte[] byteArray = encoding.GetBytes(pXmlString);
            return byteArray;
        }

2 个答案:

答案 0 :(得分:6)

首先,您要从XML创建MemoryStream读取。然后,您正在为该流创建XmlTextWriter。为什么呢?

我怀疑你可以摆脱第二个使用声明:

using (MemoryStream stream = new MemoryStream(StringToUTF8ByteArray(xml)))
{
    return (T)new XmlSerializer(typeof(T)).Deserialize(stream);
}

话虽如此,你的StringToUTF8ByteArray方法做什么并不清楚 - 它只是:

return Encoding.UTF8.GetBytes(text);

?如果是这样,那可能是正确的做法 - 如果原始XML是在其他编码中,那么XML声明会说一件事,而流将包含用另一种编码编码的文本。 .. 不好。你可能会更好:

using (TextReader reader = new StringReader(xml))
{
    return (T)new XmlSerializer(typeof(T)).Deserialize(XmlReader.Create(reader));
}

答案 1 :(得分:1)

看起来您可能需要XmlTextReader而不是XmlTextWriter?我用它来序列化到一个文件。您可能想要使用类似的东西:

/// <summary>
/// Serialize an object into XML and save to a file
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="value"></param>
/// <param name="filePath"></param>
public static void SerializeToXml<T>(T value, string filePath) where T : class
{
    using (FileStream stream = new FileStream(filePath, FileMode.Create))
    {
        System.Xml.Serialization.XmlSerializer x = new System.Xml.Serialization.XmlSerializer(typeof(T));
        x.Serialize(stream, value);
    }
}

/// <summary>
/// Deserialize an XML File into an object
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="filePath"></param>
/// <returns></returns>
public static T DeserializeFromXml<T>(string filePath) where T : class
{
    using (StreamReader stream = new StreamReader(filePath))
    {
        System.Xml.Serialization.XmlSerializer x = new System.Xml.Serialization.XmlSerializer(typeof(T));
        return (T)x.Deserialize(stream);
    }
}