我想迭代嵌套到组和部分中的一组输入, 目标是在每个组和部分中执行验证
<script src="jquery/jquery.js"></script>
<div id="groupA" class="preGroups">
<div id="section-A1">
<input name="SRPR1" type="text">
<input name="SRPR2" type="text">
</div>
<div id="section-A2">
<input name="SRPR1" type="text">
<input name="SRPR2" type="text">
</div>
<div id="section-A3">
<input name="SRPR1" type="text">
<input name="SRPR2" type="text">
</div>
<div id="section-A4">
<input name="SRPR1" type="text">
<input name="SRPR2" type="text">
</div>
</div>
<div id="groupB" class="preGroups">
<div id="section-B1">
<input name="SRPR1" type="text">
<input name="SRPR2" type="text">
</div>
<div id="section-B2">
<input name="SRPR1" type="text">
<input name="SRPR2" type="text">
</div>
<div id="section-B3">
<input name="SRPR1" type="text">
<input name="SRPR2" type="text">
</div>
</div>
<script>
// capture all groups
groups = $('div#[id^=group]');
console.log(groups);
// iterate through each group in groups
$.each(groups, function(key, group) {
console.log(group);
// iterate through each section in group
sections = $('div#[id^=section]');
$.each(sections, function(key, section) {
console.log(section);
// iterate inputs in each group
// more code goes here
/// console.log(input.name + " " + input.value);
});
});
答案 0 :(得分:0)
您可能需要sections = $(group).find('div#[id^=section]');
而不是sections = $('div#[id^=section]');
完整代码:
groups = $('div[id^="group"]');
//console.log(groups);
// iterate through each group in groups
$.each(groups, function(key, group) {
//console.log(group);
// iterate through each section in group
sections = $(group).find('div[id^="section"]');
$.each(sections, function(key, section) {
//console.log(section);
var inputs = $(section).find("input");
// iterate inputs in each group
// more code goes here
inputs.each(function(){
console.log(this.name + " " + this.value);
})
/// console.log(input.name + " " + input.value);
});
});