不能100%确定我的问题措辞是否正确,因为我不完全理解我的问题。
对于我的课程,我需要创建自己的智能指针,以便自行清理。
到目前为止,这是我的代码:
部首:
class Test
{
public:
Test()
{
m_iTest1 = 4;
m_iTest2 = 3;
m_iTest3 = 2;
m_iTest4 = 1;
}
Test (int a, int b, int c, int d)
{
m_iTest1 = a;
m_iTest2 = b;
m_iTest3 = c;
m_iTest4 = d;
}
Test(const Test& a_oTest)
{
m_iTest1 = a_oTest.m_iTest1;
m_iTest2 = a_oTest.m_iTest2;
m_iTest3 = a_oTest.m_iTest3;
m_iTest4 = a_oTest.m_iTest4;
}
~Test(){;}
int m_iTest1;
int m_iTest2;
int m_iTest3;
int m_iTest4;
};
template<class T>
class SmartData
{
public:
template<class T> friend class SmartPointer;
SmartData();
SmartData(const T& a_oData);
~SmartData();
T operator * () const;
unsigned int GetCount(){return m_uiCount;}
protected:
void IncrementCount(){++m_uiCount;}
void DecrementCount();
void DeleteThis();
unsigned int m_uiCount;
T* m_poData;
};
template<class T>
class SmartPointer
{
public:
SmartPointer();
SmartPointer(SmartData<T>& a_oSmartData);
SmartPointer(const SmartPointer& a_oSmartPointer);
~SmartPointer();
SmartPointer<T>& operator = (const SmartPointer<T>& a_oSmartPointer);
T operator *() const;
SmartData<T>* operator ->() const;
unsigned int GetCount() const;
private:
SmartData<T>* m_poSmartData;
};
#include "smartpointer.inl"
内联文件:
template<class T>
SmartData<T>::SmartData()
{
m_uiCount = 0;
m_poData = new T();
}
template<class T>
SmartData<T>::SmartData(const T& a_oData)
{
m_uiCount = 0;
m_poData = new T(a_oData);
}
template<class T>
SmartData<T>::~SmartData()
{
if (m_poData)
{
delete m_poData;
}
}
template<class T>
T SmartData<T>::operator * () const
{
return *m_poData;
}
template<class T>
void SmartData<T>::DecrementCount()
{
if (m_uiCount - 1 == 0 || m_uiCount == 0)
{
DeleteThis();
return;
}
--m_uiCount;
}
template<class T>
void SmartData<T>::DeleteThis()
{
if (m_poData)
{
delete m_poData;
m_poData = 0;
}
}
template<class T>
SmartPointer<T>::SmartPointer()
{
m_poSmartData = new SmartData<T>();
m_poSmartData->IncrementCount();
}
template<class T>
SmartPointer<T>::SmartPointer(SmartData<T>& a_oSmartData)
{
m_poSmartData = &a_oSmartData;
m_poSmartData->IncrementCount();
}
template<class T>
SmartPointer<T>::SmartPointer(const SmartPointer& a_oSmartPointer)
{
m_poSmartData = a_oSmartPointer.a_oSmartData;
m_poSmartData->IncrementCount();
}
template<class T>
SmartPointer<T>::~SmartPointer()
{
m_poSmartData->DecrementCount();
m_poSmartData = 0;
}
template<class T>
SmartPointer<T>& SmartPointer<T>::operator = (const SmartPointer<T>& a_oSmartPointer)
{
m_poSmartData = a_oSmartPointer.m_poSmartData;
m_poSmartData->IncrementCount();
}
template<class T>
T SmartPointer<T>::operator *() const
{
return *m_poSmartData->m_poData;
}
template<class T>
SmartData<T>* SmartPointer<T>::operator ->() const
{
return m_poSmartData;
}
template<class T>
unsigned int SmartPointer<T>::GetCount() const
{
return m_poSmartData->m_uiCount;
}
的main.cpp
void SomeFunction1(SmartData<Test>& a_SmartData)
{
SmartPointer<Test> oSmartPointer2(a_SmartData);
}
void main()
{
SmartData<int> oSmartData1(5);
if (1)
{
SmartPointer<int> oSmartPointer1(oSmartData1);
int iTemp1 = oSmartPointer1->GetCount();
int iTemp2 = *oSmartPointer1;
int iTemp3 = *oSmartData1;
}
if (1)
{
SmartData<int> oSmartData2(5);
}
SmartData<Test> oSmartData3;
(*oSmartData3).m_iTest1 = 5; //Does not work
if (1)
{
SmartData<Test> oSmartData4(oSmartData3);
SomeFunction1(oSmartData3);
//oSmartData4 still exits
}
}
一切正常,数据自我清理后我没有泄漏......除了一行:
(*oSmartData3).m_iTest1 = 5;
我正在使用visual studio编译,当我放置“。”时。在“(* oSmartData3)”之后...“m_iTest1”正确显示。除了我收到错误: 错误C2106:'=':左操作数必须是l值
我不确定为什么这不起作用或改变什么,所以它确实有用。
答案 0 :(得分:4)
仔细观察SmartData中的运算符*()声明:
T operator * () const;
这意味着此运算符返回T类型的对象,该对象是m_poSmartData->m_poData
的副本。在这种情况下,它是一个临时对象:
(*oSmartData3).m_iTest1 = 5; //Does not work
当然,您不能为临时对象赋值,因为它不是l值。阅读更多关于l值和r值的信息:http://publib.boulder.ibm.com/infocenter/comphelp/v7v91/index.jsp?topic=%2Fcom.ibm.vacpp7a.doc%2Flanguage%2Fref%2Fclrc05lvalue.htm
我建议您返回对m_poSmartData->m_poData
的引用
在operator *()中(如果我正确理解你要做的事情)。
答案 1 :(得分:2)
您的T operator *() const
正在返回一个临时对象(即副本),该对象不是l值(无法分配)。改为引用参考:
T& operator *() const;
答案 2 :(得分:0)
这是否有效:
oSmartData3.m_iTest1 = 5;