Question

这适用于phpmyadmin，但是当我在代码上使用时给了我和错误，错误说，解析错误：语法错误，意外'％'....

我的sintax错误＆gt;？

    <?php

$database =& JFactory::getDBO(); 

//Declare Variables
$user = JFactory::getUser();
$id = $user->get('id');
$name = $user->get('name');

// Display quizzes
echo "</br>";
echo "Quizzes History for : " ;
echo "<b>";
echo $name;
echo "</b>";


echo "</br>";
echo "</br>";

$database->setQuery(" SELECT distinct qui.title AS name,   

( SELECT GROUP_CONCAT(profiles.title)

  FROM jos_jquarks_users_profiles AS users_profiles    
  LEFT JOIN jos_jquarks_profiles AS profiles ON users_profiles.profile_id = profiles.id     
  WHERE users_profiles.user_id = sessionWho.user_id ) AS profile,    
   ( SELECT sum(score) 
 FROM jos_jquarks_quizzes_answersessions     

  WHERE quizsession_id = quizSession.id              AND status <> -1 ) AS score, 

( SELECT count(distinct question_id)              FROM jos_jquarks_quizzes_answersessions            
  WHERE quizsession_id = quizSession.id ) AS maxScore,            
DATE_FORMAT(quizSession.finished_on,'%M %d, %Y') 
 FROM jos_jquarks_quizsession AS quizSession  

LEFT JOIN jos_jquarks_users_quizzes AS users_quizzes ON users_quizzes.id = quizSession.affected_id    
LEFT JOIN jos_jquarks_quizzes AS qui ON users_quizzes.quiz_id = qui.id     
LEFT JOIN jos_jquarks_quizzes_answersessions AS quizSessAns ON quizSessAns.quizsession_id = quizSession.id 
LEFT JOIN jos_jquarks_sessionwho AS sessionWho ON sessionWho.session_id = quizSession.id        
LEFT JOIN jos_jquarks_users_profiles AS users_profiles ON users_profiles.user_id = sessionWho.user_id 
LEFT JOIN jos_jquarks_profiles AS profiles ON profiles.id = users_profiles.profile_id   
WHERE sessionWho.user_id =  ' .$id  " ) ;


if (!$database->query()) { //write data and if error occurs alert
    echo "<script> alert('".$database->getErrorMsg()."'); </script>";
}

//var_dump($database);
$tableStyle = "padding: 5px;border:1px"; 
$tdStyle = "padding:5px "; 
$thStyle = "padding:7px ";

echo '<table style="' . $tableStyle . '" cellpadding="7" cellspacing="7">'; 
echo "<tr> <th style=align:center>Quiz Title </th><th style=align:center> Score </th><th>Maximum Score </th><th> Unanswered </th> <th>Finished On </th></tr>"; 

$row = $database->loadRowList();
foreach($row as $valuearray)
{
echo '<tr style=" align="center">';
foreach($valuearray as $field)
{

echo "<td>$field</td>";
}
echo "</tr>";
}
echo "</table>";

?>

Answer 1

你必须逃脱'标记。而不是

    DATE_FORMAT(quizSession.finished_on,'%M %d, %Y')

试

    DATE_FORMAT(quizSession.finished_on,\'%M %d, %Y\')

或者你可以使用双引号“来开始和结束字符串。

Answer 2

这是因为你的字符串被单引号$database->setQuery('终止 - 只需更改为双引号即可。

$database->setQuery(" ");

如何在我的查询中使用DATE FORMAT？

2 个答案: