Question

我坚持使用SQL查询。

考虑下表：

Table DG_GAME_ROUNDS    
RoundId int
GameId  int
RoundNumber int
Value   varchar(20)
Guess   varchar(20)
Answer  varchar(20)
Correct bit
Minutes int
Seconds int
Milliseconds    int

此表包含游戏回合的结果。现在，有时候你可以用手指对游戏做出回答，然后猜测时间为35或甚至0毫秒。这些答案扭曲了我的游戏结果，我想删除它们。

我想弄清楚猜测至少200毫秒长的平均猜测时间。因此，如果一个游戏有五轮，猜测为455,400,340,30,300。我想忽略30并平均剩下的四个值并获得374的平均猜测时间。不降低30的平均猜测时间将是305.

我的问题是我正在尝试加入两个子查询，并且我收到一条错误消息，指出“on”语句周围存在问题。我认为允许加入子查询。

 select vt.gameid, vt.totalms, vt.numofguesses, vt.correctguesses
from
(select    gr.gameid 
       ,  sum((gr.seconds*1000) + gr.milliseconds) as totalms
       ,  count(gr.roundid) as numofguesses
       ,  sum(cast(gr.correct as int)) as correctguesses
          from work_tables.dbo.dg_game_rounds gr (nolock)            
          group by gr.gameid 
  ) vt 
inner join  (
              select vtIII.gameid, vtIII.avgtime
              from 
                  (
                     select vtII.gameid, sum(vtII.avgms)/count(vtII.avgms) as avgtime
                     from (
                              select gr.gameid, gr.seconds * 1000 + gr.milliseconds as avgms
                              from dg_game_rounds gr (nolock)
                              where gr.seconds * 1000 + gr.milliseconds > 200
                          ) vtII
                     group by vtII.gameid
                   ) vtIII 
 on vtIII.gameid = vt.gameid

Answer 1

因为你错过了一个结尾）（倒数第二行）

select vt.gameid, vt.totalms, vt.numofguesses, vt.correctguesses
from
(select    gr.gameid 
       ,  sum((gr.seconds*1000) + gr.milliseconds) as totalms
       ,  count(gr.roundid) as numofguesses
       ,  sum(cast(gr.correct as int)) as correctguesses
          from work_tables.dbo.dg_game_rounds gr (nolock)            
          group by gr.gameid 
  ) vt 
inner join  (
              select vtIII.gameid, vtIII.avgtime
              from 
                  (
                     select vtII.gameid, sum(vtII.avgms)/count(vtII.avgms) as avgtime
                     from (
                              select gr.gameid, gr.seconds * 1000 + gr.milliseconds as avgms
                              from dg_game_rounds gr (nolock)
                              where gr.seconds * 1000 + gr.milliseconds > 200
                          ) vtII
                     group by vtII.gameid
                   ) vtIII ) vtIII
 on vtIII.gameid = vt.gameid

Answer 2

您尚未关闭所有子查询：

select vt.gameid, vt.totalms, vt.numofguesses, vt.correctguesses
from
(select    gr.gameid 
       ,  sum((gr.seconds*1000) + gr.milliseconds) as totalms
       ,  count(gr.roundid) as numofguesses
       ,  sum(cast(gr.correct as int)) as correctguesses
          from work_tables.dbo.dg_game_rounds gr (nolock)            
          group by gr.gameid 
  ) vt 
inner join  (
              select vtIII.gameid, vtIII.avgtime
              from 
                  (
                     select vtII.gameid, sum(vtII.avgms)/count(vtII.avgms) as avgtime
                     from (
                              select gr.gameid, gr.seconds * 1000 + gr.milliseconds as avgms
                              from dg_game_rounds gr (nolock)
                              where gr.seconds * 1000 + gr.milliseconds > 200
                          ) vtII
                     group by vtII.gameid
                   ) vtIII ) f
 on f.gameid = vt.gameid

我添加了这个：) vtIII ) f

Answer 3

计算括号。

inner join  (

永远不会关闭。

SQL Puzzle - 为什么我不能加入这两个子查询？

3 个答案: