Question

我有以下原始HTTP请求：

GET http://www.google.ie/ HTTP/1.1
Host: www.google.ie
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:5.0) Gecko/20100101 Firefox/5.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-us,en;q=0.5
Accept-Encod...

我正试图从我的localhost发送这个。有人能指出我在C或C ++中如何做到这一点的正确方向吗？

我目前正在寻找套接字，但它并没有真正起作用。

   int sockfdi, portnoi, ni;
   struct sockaddr_in serv_addri;
   struct hostent *serveri;
   portnoi =80;

   sockfdi = socket(AF_INET, SOCK_STREAM, 0);
   if (sockfdi < 0){
        error("***ERROR opening socket");
   }
   serveri = gethostbyname("172.16.1.218");
   if (serveri == NULL){
       fprintf(stderr,"***ERROR, no such host\n");
       exit(0);
   }

   bzero((char *) &serv_addri, sizeof(serv_addri));
   serv_addri.sin_family = AF_INET;
   bcopy((char *)serveri->h_addr, (char *)&serv_addri.sin_addr.s_addr, serveri->h_length);
   serv_addri.sin_port = htons(portnoi);
   if (connect(sockfdi,(struct sockaddr *) &serv_addri,sizeof(serv_addri)) < 0){
       error("***ERROR connecting");
   }
   printf("Please enter the message: ");
   bzero(buffer,256);

Answer 1

您可以尝试使用libcurl代替套接字：

#include <stdio.h>
#include <curl/curl.h>

int main(void)
{
  CURL *curl;
  CURLcode res;
  struct curl_slist *headers = NULL;

  curl = curl_easy_init();
  if(curl) {
    headers = curl_slist_append(headers, "Host: www.google.ie");
    headers = curl_slist_append(headers, "User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:5.0) Gecko/20100101 Firefox/5.0");
    headers = curl_slist_append(headers, "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8");
    headers = curl_slist_append(headers, "Accept-Language: en-us,en;q=0.5");
    /* Add more headers here */
    curl_easy_setopt(curl, CURLOPT_URL, "http://www.google.ie/");
    curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
    res = curl_easy_perform(curl);

    /* always cleanup */ 
    curl_slist_free_all(headers);
    curl_easy_cleanup(curl);
  }
  return 0;
}

发送原始http标头

1 个答案: