我在mysql语句中需要一些帮助 Ive table1有7列,表2有8列额外列名为ranking,我的语句应该是这样的 从表1中选择全部然后按“用户数量”对其进行排序,将其插入表2并排名开始1 2 3等,
table 1 :
username | email | number of users
jack a@a.com 75
ralf b@b.com 200
anne c@c.com 12
sonny d@d.com 300
===================================
这里我需要根据用户数量进行INSERT和RANKING
table 2
ranking | username | email | number of users
1
2
3
答案 0 :(得分:2)
我会避免使用另一张桌子。单个查询就足够了。
create table mytable (
id int not null auto_increment primary key,
username varchar(50),
email varchar(50),
number int
) engine = myisam;
insert into mytable (username,email,number)
values
('a','aaa',10),
('b','bbb',30),
('c','ccc',50),
('d','ddd',30),
('e','eee',20),
('f','fff',45),
('g','ggg',20);
select @r:=@r+1 as rnk,username,email,number
from mytable,(select @r:=0) as r order by number desc
+------+----------+-------+--------+
| rnk | username | email | number |
+------+----------+-------+--------+
| 1 | c | ccc | 50 |
| 2 | f | fff | 45 |
| 3 | b | bbb | 30 |
| 4 | d | ddd | 30 |
| 5 | e | eee | 20 |
| 6 | g | ggg | 20 |
| 7 | a | aaa | 10 |
+------+----------+-------+--------+
7 rows in set (0.00 sec)
这是一个考虑关系的更智能的版本
select @r:=@r + 1 as rn, username,email,
@pos:= if(@previous<>number,@r,@pos) as position,
@previous:=number as num
from mytable,(select @r:=0,@pos:=0,@previuos:=0) as t order by number desc
+------+----------+-------+----------+--------+
| rn | username | email | position | num |
+------+----------+-------+----------+--------+
| 1 | c | ccc | 1 | 50 |
| 2 | f | fff | 2 | 45 |
| 3 | b | bbb | 3 | 30 |
| 4 | d | ddd | 3 | 30 |
| 5 | e | eee | 5 | 20 |
| 6 | g | ggg | 5 | 20 |
| 7 | a | aaa | 7 | 10 |
+------+----------+-------+----------+--------+
7 rows in set (0.00 sec)
答案 1 :(得分:1)
INSERT INTO table2
SELECT @rank := @rank + 1, table1.* FROM table1
JOIN( SELECT @rank := 0 ) AS init
ORDER BY number_of_users DESC
答案 2 :(得分:0)
你需要做这样的事情:
SELECT * FROM `table1`
INNER JOIN `table2` USING ([a common filed name here])
ORDER BY table2.[the filed name here]