Question

我正在尝试使用ksoap库从Android客户端调用Web服务。

这是我的安卓代码

private static final String SOAP_ACTION = "http://tempuri.org/HelloWorld";
private static final String METHOD_NAME = "HelloWorld";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://192.16.0.230/WebService/Test.asmx";
TextView tv;

public void call()
{
    try {

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

        request.addProperty("name", "zawoad");

        SoapSerializationEnvelope envelope = new          SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

        androidHttpTransport.call(SOAP_ACTION, envelope);

        String result = (String)envelope.getResponse();

        tv.setText(result);
    } catch (Exception e) {
        tv.setText("exception :" + e.getLocalizedMessage());
        }
}

这是我的Web服务方法，用Test.asmx文件编写

[WebMethod]
public string HelloWorld(string name)
{
    return "Hello World" + name;
}

执行androidHttpTransport.call(SOAP_ACTION, envelope);行时，会抛出以下异常

org.xmlpull.v1.XmlPullParserException：expected：START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope（position：START_TAG @ 2:44 in java.io.InputStreamReader@43e593c8）

请帮助..

Answer 1

这是正常工作的代码

private static final String SOAP_ACTION = "http://tempuri.org";
private static final String METHOD_NAME = "HelloWorld";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://192.16.0.230/WebService/Test.asmx?wsdl";
/*write ?wsdl only for local system testing*/

TextView tv;

public void call()
{
    try {

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

        request.addProperty("name", "zawoad");

        SoapSerializationEnvelope envelope = new          SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL,20000);//Updated

        androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive  resultsRequestSOAP = (SoapPrimitive) envelope.getResponse();
        String result = resultsRequestSOAP.toString();

        tv.setText(result);
    } catch (Exception e) {
        tv.setText("exception :" + e.getLocalizedMessage());
        }
}

Answer 2

你正在表演的召唤不会发生。什么是Web服务返回类型？我们可以传递值并调用它。

无法从Android客户端调用C＃.net Web Service方法

2 个答案: