Question

我们如何传递字符串Mr.X＆amp;先生在URL中。

我已经尝试了这个但是这个人做了所有的角色但是＆符号。

[urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]

Answer 1

甚至更短：

@implementation NSString (Escaping)
- (NSString*)stringWithPercentEscape {            
    return [(NSString *) CFURLCreateStringByAddingPercentEscapes(
        NULL, 
        (CFStringRef)[[self mutableCopy] autorelease], 
        NULL, 
        CFSTR("=,!$&'()*+;@?\n\"<>#\t :/"),
        kCFStringEncodingUTF8) autorelease];
}
@end

这里又是一个ARC符合内联函数的帮助器：

#if __has_feature(objc_arc)
static inline NSString *hxURLEscape(NSString *v) {
    static CFStringRef _hxURLEscapeChars = CFSTR("=,!$&'()*+;@?\r\n\"<>#\t :/");
    return ((__bridge_transfer NSString *)CFURLCreateStringByAddingPercentEscapes(
        NULL, 
        (__bridge CFStringRef)[v mutableCopy], 
        NULL, 
        _hxURLEscapeChars, 
        kCFStringEncodingUTF8));
}
#endif

Answer 2

-stringByAddingPercentEscapesUsingEncoding:不执行完整的转义编码。您应该使用-replaceOccurrencesOfString:withString:

手动添加编码

这是https://devforums.apple.com/message/15674#15674最初建议的完整列表（镜像Gamecat的列表）。正如Nick指出的那样，这很昂贵，所以不要只考虑完整列表而不考虑你逃避的实际要求。

NSMutableString *escaped = [actionString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];   
[escaped replaceOccurrencesOfString:@"$" withString:@"%24" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"&" withString:@"%26" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"+" withString:@"%2B" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"," withString:@"%2C" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"/" withString:@"%2F" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@":" withString:@"%3A" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@";" withString:@"%3B" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"=" withString:@"%3D" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"?" withString:@"%3F" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"@" withString:@"%40" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@" " withString:@"%20" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"\t" withString:@"%09" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"#" withString:@"%23" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"<" withString:@"%3C" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@">" withString:@"%3E" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"\"" withString:@"%22" options:NSCaseInsensitiveSearch range:wholeString];
[escaped replaceOccurrencesOfString:@"\n" withString:@"%0A" options:NSCaseInsensitiveSearch range:wholeString];

此代码肯定会对您的网址进行哈希处理。

Answer 3

使用％26作为网址转义。

其他逃脱：

$  %24
&  %26
+  %2B
,  %2C
/  %2F
:  %3A
;  %3B
=  %3D
?  %3F
@  %40

Answer 4

stringByAddingPercentEscapesUsingEncoding也无法与+一起正常使用。

这是一个更简单的解决方案：

[[[urlString stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding] stringByReplacingOccurrencesOfString:@"&" withString:@"%26"] stringByReplacingOccurrencesOfString:@"+" withString:@"%2b"];

Answer 5

CFURLCreateStringByAddingPercentEscapes已被弃用（自iOS9开始），那么如何修改URLQueryAllowedCharacterSet以删除保留的字符，从而允许对它们进行有效的百分比编码？？

- (NSString *)URLQueryValueEncodedString:(NSString *)string {
    static NSMutableCharacterSet *_allowedCharacterSet = nil;
    static dispatch_once_t onceToken;
    dispatch_once(&onceToken, ^{
        NSString *reservedCharacters = @"=,!$&'()*+;@?\r\n\"<>#\t :/[]%";
        _allowedCharacterSet = [NSCharacterSet URLQueryAllowedCharacterSet].mutableCopy;
        [_allowedCharacterSet removeCharactersInString:reservedCharacters];
    });

    return [string stringByAddingPercentEncodingWithAllowedCharacters:_allowedCharacterSet];
}

Answer 6

在URL中，＆符号是受保护的关键字，表示包含查询字符串变量。你不能把它作为价值本身的一部分。您需要将其更改为其他内容。

以下链接指向StackOverflow上提出的相同问题：ASP.Net URLEncode Ampersand for use in Query String

iOS：URL字符串中的＆符问题

6 个答案: