Question

嘿伙计们我正在尝试制作一个php脚本来检查文本框是否为空，我使用的是以下代码。

<?php
$dbname = $_POST['db_name'];
$dbuser = $_POST['db_user'];
$dbpass = $_POST['db_pass'];
$username = $_POST['username'];
$password = $_POST['password'];

if($dbname == "" || $dbuser == "" || $dbpass == "" || $username == "" || $password == "")
{
Echo("Missing Information!");
}else{
Echo("Success!");
}
?>

以下是我的表单代码：

    <form method="post" style="padding-left: 50px" action="install_submit.php">
<h2>Database connection settings</h2>
<label for="db_name">Database name:</label>
<input type="textbox" id="db_name" name="db_name" /><br/>
    <label for="db_user">Database username:</label>
    <input type="textbox" id="db_user" name="db_user" /><br/>
<label for="db_pass">Database password:</label>
<input type="password" id="db_pass" name="db_pass" /><br/>
<h2>CPanel settings</h2>
<label for="username">Username:</label>
<input type="textbox" id="username" name="username" /><br/>
<label for="password">Password:</label>
<input type="password" id="password" name="password" /><br/>


<input type="submit" name="submit_install" value="Install" />
</form>

随着它总是返回“缺少信息！”即使填写了所有文本框。

我做错了什么？

Answer 1

改为使用empty()，

if (empty($dbname) || empty($dbuser) || empty($dbpass) || empty($username) || empty($password)) {
    //Empty
}
else {
    //Not Empty
}

检查输入的 name 是否正确。

Answer 2

要进行调试，请尝试执行

print_r($_POST);

查看您在$ _POST变量中实际收到的内容，然后在if语句中一次尝试一次比较。也许它会让你看到幕后。

Answer 3

替换此＆amp;检查是否获得所有参数值。

<?php
$dbname = $_POST['db_name'];
$dbuser = $_POST['db_user'];
$dbpass = $_POST['db_pass'];
$username = $_POST['username'];
$password = $_POST['password'];

echo "<pre>";
print_r($_POST);
echo "</pre>";
die();

if($dbname == "" || $dbuser == "" || $dbpass == "" || $username == "" || $password == ""){
    echo("Missing Information!");
}else{
    echo("Success!");
}
?>

Answer 4

要检查发布的数据，您可以使用isset()。

确定变量是否已设置且不是NULL

if(!isset($dbname) || trim($dbname) == '')
{
   echo "You did not fill out the required fields.";
}

trim()关键字删除empty()忽略的空格。

检查文本框是否为空？

4 个答案: