我在网上找到了以下mssql查询,该查询应该可以帮助我解决我几天来一直在努力解决的复杂mysql查询问题。
SELECT
inv.typeID AS typeID,
inv.typeName AS typeName,
invGroups.groupName AS groupName,
inv.published AS published,
inv.description AS description,
rankVal.valueFloat AS rank,
replace (( SELECT skills.attributeName AS [data()]
FROM dgmTypeAttributes tattr -- Link between skillbook and attributes
INNER JOIN dgmAttributeTypes skills ON (skills.attributeID = tattr.valueInt)
WHERE (tattr.typeID = inv.typeID)
AND (tattr.attributeID IN (180, 181)) -- Primary and secondary attributes
ORDER BY inv.typeID FOR xml path('')), ' ', ',') AS prisec,
replace (( SELECT RTRIM(CAST(inv2.typeID AS varchar)) + ',' AS [data()]
FROM (SELECT * FROM dgmTypeAttributes WHERE (attributeID in (182, 183, 184)) -- Pre-req skills 1, 2, and 3
AND (typeID = inv.typeID)) tattr2
INNER JOIN invTypes inv2 ON (tattr2.valueInt = inv2.typeID)
ORDER BY inv.typeID FOR xml path('')), ' ', ' ') AS prereq,
replace (( SELECT RTRIM(CAST(tattr2.valueInt AS varchar)) + ',' AS [data()]
FROM (SELECT * FROM dgmTypeAttributes WHERE (attributeID in (277, 278, 279)) AND (typeID = inv.typeID)) tattr2 -- Link between skillbook and attributes
ORDER BY inv.typeID FOR xml path('')), ' ', ' ') AS prereqlvl
FROM invTypes inv
INNER JOIN invGroups ON (inv.groupID = invGroups.groupID)
INNER JOIN dgmTypeAttributes rankVal ON (inv.typeID = rankVal.typeID)
WHERE invGroups.categoryID = 16 -- Skillbooks category
AND rankVal.attributeID = 275 -- Skill rank attribute
AND inv.published = 1
GROUP BY inv.typeID, inv.typeName, invGroups.groupName, inv.published, inv.description, rankVal.valueFloat
ORDER BY invGroups.groupName, inv.typeName
我是如此使用mysql但我对mssql一无所知。有人可以推荐一种很好的方法来转换这个低或现在成本的查询吗?我不希望有人为我转换它,因为这会要求太多,但一些建议会指向我在仪式方向(除了学习mssql lolz)将是非常好的。感谢您的时间和耐心。