Question

我有NSDictionary看起来像。

dic is : {
city = #;
country = #;
date = "2011-08-12 05:00:00 +0000";
"day_of_week" = Fri;
high = 79;
icon = "/ig/images/weather/chance_of_storm.gif";
low = 61;
startdate = "2011-08-12 05:00:00 +0000";
state = #;
}


dic is : {
city = #;
country = #;
date = "2011-08-13 05:00:00 +0000";
"day_of_week" = Fri;
high = 79;
icon = "/ig/images/weather/chance_of_storm.gif";
low = 61;
startdate = "2011-08-12 05:00:00 +0000";
state = #;

}

dic is : {
city = #;
country = #;
date = "2011-08-14 05:00:00 +0000";
"day_of_week" = Sat;
high = 79;
low = 58;
startdate = "2011-08-12 05:00:00 +0000";
state = #;

}

if(( [dd1 earlierDate:startDate]) &&[dd1 earlierDate:endDate] ) 

                {     
                    /*if([dd1 isEqualToDate:startDate] || [dd1 isEqualToDate:endDate] )

我正在从测试用例中传递NSDate。从测试用例传递Startdate和enddate，并从作为日期的解析器传递dd1。我想获得2个日期之间的值，但获得所有4个日期。只获取我希望的日期值的解决方案是什么？

DD1是NSDATE对象我正在从NSDICTIONARY.SO DD1开始运行在我所在的FORCH中，我将在201-08-12,2011-08-13 ETC获取日期

Answer 1

您正在尝试将NSDictionary与NSDate进行比较。这是您提取日期和计算差异的方法：

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"yyyy-mm-dd HH:mm:ss zz"];
NSDate *startDate = [formatter dateFromString:[dd1 objectForKey:@"startdate"]];
NSDate *date = [formatter dateFromString:[dd1 objectForKey:@"date"]];
NSTimeInterval intervalInSeconds = [startDate timeIntervalSinceDate:date];
[formatter release];

不是100％确定dateFormate字符串的最后一部分，但它应该有效。

Answer 2

从您发布的代码中，您所谈论的4个日期并不明显。但是，当您尝试将boolean逻辑应用于对象时，if语句没有意义（earlyDate：返回指向NSDate对象的指针）。尝试这样的事情：

if(([dd1 compare:startDate] == NSOrderedDescending) && ([dd1 compare:endDate] == NSOrderedAscending))

如果dd1表示的日期介于startDate和endDate之间，则此值应仅为true。

从nsdictionary中选择特定日期

2 个答案: