Question

我最近了解到我可以使用此命令运行服务器：

sudo python -m HTTPSimpleServer

我的问题：完成后如何终止此服务器？

Answer 1

键入Control-C。就这么简单。

Answer 2

您可能需要检查this servlet module中的HttpServer类以获取允许服务器退出的修改。如果处理程序引发SystemExit异常，则服务器将中断其服务。

class HttpServer(socketserver.ThreadingMixIn, http.server.HTTPServer):

    """Create a server with specified address and handler.

    A generic web server can be instantiated with this class. It will listen
    on the address given to its constructor and will use the handler class
    to process all incoming traffic. Running a server is greatly simplified."""

    # We should not be binding to an
    # address that is already in use.
    allow_reuse_address = False

    @classmethod
    def main(cls, RequestHandlerClass, port=80):
        """Start server with handler on given port.

        This static method provides an easy way to start, run, and exit
        a HttpServer instance. The server will be executed if possible,
        and the computer's web browser will be directed to the address."""
        try:
            server = cls(('', port), RequestHandlerClass)
            active = True
        except socket.error:
            active = False
        else:
            addr, port = server.socket.getsockname()
            print('Serving HTTP on', addr, 'port', port, '...')
        finally:
            port = '' if port == 80 else ':' + str(port)
            addr = 'http://localhost' + port + '/'
            webbrowser.open(addr)
        if active:
            try:
                server.serve_forever()
            except KeyboardInterrupt:
                print('Keyboard interrupt received: EXITING')
            finally:
                server.server_close()

    def handle_error(self, request, client_address):
        """Process exceptions raised by the RequestHandlerClass.

        Overriding this method is necessary for two different reasons:
        (1) SystemExit exceptions are incorrectly caught otherwise and
        (2) Socket errors should be silently passed in the server code"""
        klass, value = sys.exc_info()[:2]
        if klass is SystemExit:
            self.__exit = value
            self._BaseServer__serving = None
        elif issubclass(klass, socket.error):
            pass
        else:
            super().handle_error(request, client_address)

    def serve_forever(self, poll_interval=0.5):
        """Handle all incoming client requests forever.

        This method has been overridden so that SystemExit exceptions
        raised in the RequestHandlerClass can be re-raised after being
        caught in the handle_error method above. This allows servlet
        code to terminate server execution if so desired or required."""
        super().serve_forever(poll_interval)
        if self._BaseServer__serving is None:
            raise self.__exit

HTTPSimpleServer - 如何关闭/终止它？

2 个答案: