Question

我在编写从mySQL数据库返回的日期时遇到问题。这是我尝试使用的代码：

<?php
function get_gold_time()
{
     $goldquery = mysql_query("SELECT * FROM metal_price WHERE metal= 'GOLD' LIMIT 0, 96"); 


         while($result = mysql_fetch_array( $goldquery )) 
 { 

        echo "'" . date_format($result['time'], 'jS ,g A') . "'" . ", " ;  
 } 

         }
?>

这是我收到的错误：

警告：date_format（）要求参数1为DateTime，在第128行的/home/bellsnet/public_html/chart.php中给出字符串 ''，

没有日期格式，我的代码如下所示：

<?php
function get_gold_time()
{
     $goldquery = mysql_query("SELECT * FROM metal_price WHERE metal= 'GOLD' LIMIT 0, 96"); 


         while($result = mysql_fetch_array( $goldquery )) 
 { 

        echo "'" .$result['time'] . "'" . ", " ;  
 } 

         }
?>

并按以下方式返回我的值：

'2011-08-10 01:15:02', '2011-08-10 01:00:02', '2011-08-10 00:45:02', '2011-08-10 00:30:02', '2011-08-10 00:15:02', '2011-08-10 00:00:02', '2011-08-09 23:45:03', '2011-08-09 23:30:02', '2011-08-09 23:15:02', '2011-08-09 23:00:03', '2011-08-09 22:45:02', '2011-08-09 22:40:22', '2011-08-09 22:30:02', '2011-08-09 22:15:02', '2011-08-09 22:13:41', '2011-08-10 02:00:02', '2011-08-10 01:45:02', '2011-08-10 01:30:02', '2011-08-10 02:15:02', '2011-08-10 02:30:02', '2011-08-10 02:45:02', '2011-08-10 03:00:02', '2011-08-10 03:15:03', '2011-08-10 03:30:03', '2011-08-10 03:45:03', '2011-08-10 04:00:03', '2011-08-10 04:15:01',

任何帮助都将非常感谢！我一直在调整这几个小时。

Answer 1

尝试日期（）

<?php
function get_gold_time()
{
     $goldquery = mysql_query("SELECT * FROM metal_price WHERE metal= 'GOLD' LIMIT 0, 96"); 


         while($result = mysql_fetch_array( $goldquery )) 
 { 

        echo "'" . date('jS ,g A', strToTime($result['time'])) . "'" . ", " ;  
 } 

         }
?>

或直接在MYSQL查询中使用DATE_FORMAT（）：

http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format

Answer 2

通过DATE_FORMAT（）在MySQL中格式化日期会好得多，因为它会更快，并为您提供所需的内容。

请参阅：http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format

date_format PHP使用mySQL调用

2 个答案: