首先我会解释一下这个案例，我有一个表格tbl_game，其结构如此。此表包含游戏开始和配对游戏的时间
| id | time | pair_id |
-----------+--------------+ ---------------
1 | 123123123 | 1 |
2 | 123168877 | 1 |
我有另一个表tbl_throws，它保存每个玩家的分数。如果您想知道，this a basic dice rolling game
| id | game_id | player_id | score |
-----------+--------------+---------------+---------|
| 1 | 1 | 1 | 2 |
| 2 | 1 | 2 | 5 |
| 3 | 1 | 1 | 9 |
| 4 | 1 | 2 | 11 |
| 5 | 2 | 1 | 7 |
| 6 | 2 | 2 | 6 |
现在，id这里是投掷ID，而不是游戏ID。在这里，每个player_id 1和2的玩家都会掷骰子两次，并且在相同的游戏中获得相应的分数，而在另一个游戏中只有一次
现在，使用这两个表，我需要创建一个记录集，即每个玩家在一个游戏中的总得分
| game_id | game_time | player1_total | player2_total|
|------------+-----------+---------------+--------------|
| 1 | 123123123 | 11 | 16 |
| 2 | 123168877 | 7 | 6 |
我尝试了很多mumbo jumbo查询，但没有任何结果给出正确的结果？ 对此有什么正确的查询？
因为，大多数答案都受到一个事实的限制，即必须知道或修复player1id和player2id。
因此，我即将提供的信息可能有助于消除混淆。
还有另一张表，其中包含玩家的信息。 tbl_pupil
结构如下
| id | unique_id | name |
|---------+---------------+----------|
| 1 | 001 | some |
| 2 | 002 | another |
并且这些玩家被统称为另一个表tbl_pair
| id | player1 | player2 |
|---------+---------------+----------|
| 1 | 1 | 2 |
So, now
select
g.id
g.time
p1.id as player1id
p1.name as player1name
t.score as player1score
p2.id as player2id
p2.name as player2name
t.score as player2score
FROM
tbl_game g,
inner join tbl_pair as pair on g.pair_id = pair.id
inner join tbl_pupil as p1 on p1.id = pair.player1
inner join tbl_pupil as p2 on p2.id = pair.player2
inner join tbl_throw as t on g.id = t.game_id
这是我的初步查询，它带来了记录集，就这样
| id | time | player1id | player1name | player1score | player2id | player2name | player2score |
----------------------------------------------------------------------------------------------------------------------------
| 1 | 12 | 1 | some | 5 | 2 | another | 2 |
| 1 | 12 | 1 | some | 5 | 2 | another | 5 |
| 1 | 12 | 1 | some | 9 | 2 | another | 9 |
| 1 | 12 | 1 | some | 11 | 2 | another | 11 |
现在我只是显示一个游戏ID的结果。我没有保存足够的知识，将上述记录分为一组，其中一列中的player1单独得分和另一列中playe2的单独得分总和。
答案 0 :(得分：4)
试试这个：
SELECT
tbl_game.id AS game_id,
tbl_game.time AS game_time,
SUM(CASE WHEN player_id = 1 THEN score ELSE 0 END) AS player1_total,
SUM(CASE WHEN player_id = 2 THEN score ELSE 0 END) AS player2_total
FROM tbl_game JOIN tbl_thorws ON tbl_game.id = tbl_throws.game_id
GROUP BY tbl_game.id
答案 1 :(得分：1)
您需要内部加入两个表，并汇总您的分数。在我使用CASE语句按玩家聚合之后，执行基本支点。
SELECT G.Id as Game_Id,
G.time as Game_Time,
SUM(CASE WHEN t.Player_id = 1 THEN t.score ELSE 0 END) as Player1_total,
SUM(CASE WHEN t.Player_id = 2 THEN t.score ELSE 0 END) as Player2_total
FROM tbl_game G
INNER JOIN tbl_throws T
ON g.id = t.game_id
GROUP BY g.ID, g.time
答案 2 :(得分：1)
这与其他一些答案类似，但关键是不依赖于玩家ID为1和2。
select
game_id = g.id,
game_time = g.time,
player1_total = SUM(case t.player_id when p.player1_id then t.score else 0 end),
player2_total = SUM(case t.player_id when p.player2_id then t.score else 0 end)
from
tbl_game g
join tbl_throws t on g.id = t.game_id
join ( --Get the player IDs for this game
select
game_id,
player1_id = MIN(player_id),
player2_id = MAX(player_id)
from
tbl_throws
group by game_id
) p
on p.game_id = t.game_id
group by
g.id, g.time
为了好玩，我已将上述内容概括为允许更多＆gt; 2名球员：
2个CTE表只显示我正在使用的测试数据
;WITH tbl_game as (
select ID = 1, time = 123123123, pair_id = 1
union select ID = 2, time = 123168877, pair_id = 1
),
tbl_throws as (
select id = 1, game_id = 1, player_id = 1, score = 2
union select id = 2, game_id = 1, player_id = 2, score = 5
union select id = 2, game_id = 1, player_id = 3, score = 5
union select id = 3, game_id = 1, player_id = 1, score = 9
union select id = 4, game_id = 1, player_id = 2, score = 11
union select id = 5, game_id = 2, player_id = 1, score = 7
union select id = 6, game_id = 2, player_id = 2, score = 6
)
select
game_id = g.id,
game_time = g.time,
player1_id = MAX(case x.player_no when 1 then t.player_id else 0 end),
player1_total = SUM(case x.player_no when 1 then t.score else 0 end),
player1_id = MAX(case x.player_no when 2 then t.player_id else 0 end),
player2_total = SUM(case x.player_no when 2 then t.score else 0 end),
player3_id = MAX(case x.player_no when 3 then t.player_id else 0 end),
player3_total = SUM(case x.player_no when 3 then t.score else 0 end),
player4_id = MAX(case x.player_no when 4 then t.player_id else 0 end),
player4_total = SUM(case x.player_no when 4 then t.score else 0 end)
/* Add more rows for the number of players permitted in a single game */
from
tbl_game g
join tbl_throws t on g.id = t.game_id
cross apply (
select player_no = COUNT(distinct player_id)
from tbl_throws sub
where sub.player_id <= t.player_id
and Sub.game_id = t.game_id
) x
group by
g.id, g.time
答案 3 :(得分：0)
我认为这应该可以做你想做的事。
SELECT
tbl_game.id as game_id,
tbl_game.time as game_time,
SUM(player1.score) as player1_total,
SUM(player2.score) as player2_total
FROM tbl_game
INNER JOIN tbl_throws player1 ON player1.game_id = tbl_game.id AND player1.player_id = 1
INNER JOIN tbl_throws player2 ON player2.game_id = tbl_game.id AND player2.player_id = 2
GROUP BY tbl_game.id, tbl_game.time
答案 4 :(得分：0)
SELECT t.game_id
, t.game_time
, ( SELECT SUM(t.score)
FROM tbl_throws AS t
WHERE t.game_id = g.id
AND player_id = 1
) AS player1_total
, ( SELECT SUM(t.score)
FROM tbl_throws AS t
WHERE t.game_id = g.id
AND player_id = 2
) AS player2_total
FROM tbl_game AS g