Question

我正在尝试编写一个我需要接受按键的应用程序，并在用户停止输入时调用函数（或者当按键之间有指定的延迟时）。

如何测量两次击键之间的时间？

Answer 1

这样的事情：

NSDate *start = [NSDate date];
// do the thing you are timing
NSDate *stop = [NSDate date];

NSTimeInterval duration = [start timeIntervalSinceDate:stop];

Answer 2

可能更好的方法是获取与每个按键相关联的NSEvent，并比较它们的-timestamp属性的差异。

Answer 3

获取当前时间，然后减去上一个当前时间。请参阅-[NSDate timeIntervalSinceDate:]。

Answer 4

您可以设置计时器以在用户停止输入后执行X时间，然后在每次用户输入内容时重新启动时间 - 这样会延迟计时器到期时间。

如果很容易在计时器上重置超时，那么不确定计算密集程度如何。

您可以选择在最后一次击键时启动计时器X时间。在到期时，您可以检查最后一次击键的时间戳，这是您在上次击键时保存的，然后您可以从（超时 - 最后击键时间）时间量开始重新启动计时器。到期时再次检查。然后，在每次击键时，如果计时器只运行最后击键的更新时间戳......

Answer 5

我认为您应该为此使用线程。为按键创建线程，并且您可以在每个线程中计算两次按键之间的时间。有关更多说明，请观看我的视频以获取确切的解决方案。

https://www.youtube.com/watch?v=sDGYM8LeZh8

请参见下面的代码：

import keyboard # keyboard library
import string   # string for capturing keyboard key codes
import time     # for capturing time

from threading import * # threads for keypresses

# get the keys
keys = list(string.ascii_lowercase)

# key listener
def listen(key):
    while True:
        global timeda   # global variable for storing time for 1st keypress
        global newda    # global variable for storing time for next keypress

        keyboard.wait(key)  # when key is presses

        # check if variables are defined
        try:
            timeda
            newda

        # this will run for the first keypress only so assign initial time to variable

        except NameError:
            timeda = time.time()
            newda  = time.time()
            print("First key is pressed at "+str(round(newda,2)))
            print('\n==========\n')

        # for all keypresses except for the first will record time here
        else:
            newda = time.time()         # assign time for next keypressed
            newtime = newda - timeda    # get difference between two keys presses

            # just to test time of first keypress
            print("Previous keypress was at "+str(round(timeda,2)))

            # just to test time of next keypress
            print("Current keypress is at "+ str(round(newda,2)))

            # convert time into seconds
            newtime = newtime % 60

            print("Difference between two keypresses is "+str(round(newtime,2)))
            print('\n==========\n')     # need some space for printing difference 
            timeda = time.time()

# creating threads for keys and assigning event and args 
threads = [Thread(target=listen, kwargs={'key':key}) for key in keys]

# calling each thread
for thread in threads:
    thread.start()


# thats it

可可：测量按键之间的时间？

5 个答案: