帮助正则表达式模式

Question

我有一个txt文件，每行都有一组随机字符串，我只需要选择只包含字符的行：1234567890qwertyuiopasdfghjklzxcvbnm -._~

我正在逐行阅读并通过char验证char，我不认为这是最好的方法，我认为RegEx是完美的。

那么有人可以帮助解决这个模式吗？

谢谢！

Answer 1

 /^[-0-9a-z._~]*$/

 ^       :: matches the start of a string/start of a line
 [       :: start of a character class, means match any one of the contained characters
 -       :: dash has a special meaning in character classes, so to avoid having it interpreted for its special meaning, list it first
 0-9     :: shorthand for 0123456789 in a character class
 a-z     :: shorthand for abcdefghijklmnopqrstuvwxyz in a character class
 ._~     :: means exactly these characters in a character class
 ]       :: end of the character class 
 *       :: match zero or more of the previous atom (in this case, the character class)
 $       :: matches the end of a string/end of a line

Answer 2

如果我理解你，你可以这样做：

/^([-0-9a-zA-Z._~]\n)+$/

不区分大小写，检查行尾并且与空行不匹配。

Answer 3

认识到正则表达式应该等同于^[1234567890qwertyuiopasdfghjklzxcvbnm\-._~]*$并不需要太多。从那里，您可以简单地缩小范围，替换为0-9，a-z等。在使用从其他人那里得到的答案之前，您应该先学习正则表达式的基础知识。