我正在尝试创建一个在多个表上运行SQL查询并从查询中输出结果表的函数。结果表将有多行。我在这方面遇到了很多困难,而且我已经阅读了建议使用RETURN NEXT
的帖子,但我也无法让它工作。根据我的理解RECORD
可以使用,因为它采用了输入数据的值。
到目前为止,这是我的代码:
CREATE OR REPLACE FUNCTION
most_docs()
RETURNS
SETOF RECORD
AS $$
DECLARE
result RECORD;
BEGIN
CREATE VIEW MOSTDOC AS
SELECT P.country, COUNT(P.country) AS cnt
FROM Producer P, Movie M, ProducerMovie PM
WHERE M.title = PM.title
AND M.year = PM.year
AND P.name = PM.name
AND M.genre = 'Documentary'
GROUP BY P.country;
SELECT DISTINCT M.country INTO result
FROM MOSTDOC M
WHERE M.cnt = (SELECT MAX(M.cnt)
FROM MOSTDOC M);
RETURN result;
END;
$$ LANGUAGE plpgsql;
非常感谢任何帮助。感谢。
---------- Word in Progress代码
CREATE OR REPLACE FUNCTION
most_docs()
RETURNS
SETOF RECORD
AS $$
DECLARE
result RECORD
BEGIN
CREATE VIEW MOSTDOC AS
SELECT P.country, COUNT(P.country) AS cnt
FROM Producer P, Movie M, ProducerMovie PM
WHERE M.title = PM.title
AND M.year = PM.year
AND P.name = PM.name
AND M.genre = 'Documentary'
GROUP BY P.country;
RETURN QUERY SELECT DISTINCT M.country
FROM MOSTDOC M
WHERE M.cnt = (SELECT MAX(M.cnt)
FROM MOSTDOC M);
END;
$$ LANGUAGE plpgsql;
答案 0 :(得分:3)
如果我正确理解你的问题,那你试图做这样的事情(对于返回setof的函数我总是使用类型)
CREATE TYPE frt_test_type AS
(
country character varying,
cnt integer,
country character varying); /* types may vary */
CREATE OR REPLACE FUNCTION
RETURNS SETOF frt_test_type AS
$BODY$DECLARE r record;
BEGIN
for r in SELECT P.country, COUNT(P.country) AS cnt,
FROM Producer P, Movie M, ProducerMovie PM
WHERE M.title = PM.title
AND M.year = PM.year
AND P.name = PM.name
AND M.genre = 'Documentary'
GROUP BY P.country;
loop
return next r;
end loop;
return;
END;$BODY$
LANGUAGE 'plpgsql'
答案 1 :(得分:0)
根据this answer,你需要的是:
RETURN QUERY SELECT DISTINCT......