我正在使用P4PHP API构建一个GUI,允许用户批量创建/更新客户端规范。只要客户端被解锁,这就行得很好,但对于锁定的客户端,API没有获取-f标志(或者至少我认为不是)。尝试保存锁定的客户端时,我收到以下错误消息。这很奇怪,因为我有一个Python脚本使用Python p4 API做同样的事情并且它使用相同的行来保存客户端,但它确实选择了-f标志。我不知道该怎么做。
[错误]:'owner1'拥有的锁定客户端'php_test_client';使用-f来 强制更新。
这是我的php代码:
$p4 = new P4(); //instantiate p4 object
$p4->port = 'perforce:1666'; //set p4 port
$p4->user = $pUser; //set p4 user
try{
$p4->connect();
$p4->run_login($pPass); //login with provided p4 pass
$client = $p4->fetch_client($cNameSub);
echo "client fetched: " . $cNameSub ."\n";
$client['Client']= $cNameSub;
$client['Description']= $cDescrSub;
$client['Owner']= $cOwnerSub;
$client['Host']= $cHostSub;
$client['Root']= $cRootSub;
$client['View']= $cViewArraySub;
$client['Options']= $cOptSub;
$p4->save_client($client,"-f");
$p4->disconnect();
echo "client" . $cNameSub . " created successfully \n\n";
} catch (P4_Exception $e) {
// output errors
echo $e->getMessage() . "\n";
foreach ($p4->errors as $error) {
echo "Error: $error\n";
}
//TODO: log errors in db
}
我也尝试使用以下行保存客户端,但它也不起作用:
//try1
$p4->input = $client;
$p4->run("client", "-f");
//try2
$p4->run("client", "-f", $client);
//try3
$p4->input = $client;
$p4->run_client("-f");
答案 0 :(得分:1)
你还需要-i标志!
这有效:
$p4->input = $client;
$p4->run_client("-i","-f");