如何分离输出数据

时间:2011-08-11 15:18:12

标签: python regex parsing pyparsing

这是我的代码:

#-------------------------------------------------------------------------------
# Name:        Mocha Rotoscoping Via Blender
# Purpose:     Make rotoscoping more efficient
#
# Author:      Jeff Owens
#
# Created:     11/07/2011
# Copyright:   (c) jeff.owens 2011
# Licence:     Grasshorse
#-------------------------------------------------------------------------------
#!/usr/bin/env python
import sys
import os
import parser
sys.path.append('Z:\_protomotion\Prog\HelperScripts')
import GetDir
sys.path.append('Z:/Blender_Roto')
filename = 'diving_board.shape4ae'
infile = 'Z:/Blender_Roto/'
#import bpy
#from mathutils import Vector

#below are taken from mocha export
x_width =2048
y_height = 778
z_depth = 0
frame = 20

import re

data_directory = 'Z:/Blender_Roto/' # windows
data_file = 'diving_board.shape4ae'
fullpath = data_directory + data_file


print("====init=====")

file = open(fullpath)
for line in file:
current_line = line

# massive room for optimized code here.

# this assumes the last element of the line containing the words
# "Units Per Second" is the number we are looking for.
# this is a non float number, generally.
if current_line.find("Units Per Second") != -1:
    fps = line_split = float(current_line.split()[-1])
    print("Frames Per Second:", fps)

# source dimensions
if current_line.find("Source Width") != -1:
    source_width = line_split = int(current_line.split()[-1])
    print("Source Width:", source_width)

if current_line.find("Source Height") != -1:
    source_height = line_split = int(current_line.split()[-1])
    print("Source Height:", source_height)

# aspect ratios
if current_line.find("Source Pixel Aspect Ratio") != -1:
    source_px_aspect = line_split = int(current_line.split()[-1])
    print("Source Pixel Aspect Ratio:", source_px_aspect)

if current_line.find("Comp Pixel Aspect Ratio") != -1:
    comp_aspect = line_split = int(current_line.split()[-1])
    print("Comp Pixel Aspect Ratio:", comp_aspect)


# assumption, ae file can contain multiple mocha shapes.
# without knowing the exact format i will limit the script
# to deal with one mocha shape being animated N frames.

# this gathers the shape details, and frame number but does not
# include error checking yet.
if current_line.find("XSpline") != -1:

    # record the frame number.

    frame = re.search("\s*(\d*)\s*XSpline", current_line)
    if frame.group(1) != None:
        frame = frame.group(1)
        print("frame:", frame)


    # pick part the part of the line that deals with geometry
    match = re.search("XSpline\((.+)\)\n", current_line)

    line_to_strip = match.group(1)
    points = re.findall('(\(.*?\))', line_to_strip)
    print(len(points))
    for point in points:
        print(point)

 file.close()

这是输出:

====init=====
Frames Per Second: 24.0
Source Width: 2048
Source Height: 778
Source Pixel Aspect Ratio: 1
Comp Pixel Aspect Ratio: 1
frame: 20
5
(0.793803,0.136326,0,0.5,0)
(0.772345,0.642332,0,0.5,0)
(0.6436,0.597615,0,0.5,0)
(0.70082,0.143387,0,0.5,0.25)
(0.70082,0.112791,0,0.5,0)

我想弄清楚如何调出给出的个别点数。例如,我怎么能让代码吐出0.793803,或者只是吐出0.136326等等

附录

所以我最终做的就是添加这个

(point1, point2, point3, point4, point5) = points
print (point1)
#print (point2)
#print (point3)
#print (point4)
#print (point5)

产生了:

(0.793803,0.136326,0,0.5,0)

但是当我再次尝试解析时,我写了

(x,y,z,w,s) = p

它出现错误p未定义

所以我试过了     (x,y,z,w,s)= point1

产生的错误值太多,无法解压缩。

我尝试的另一件事是

for point1 in points
    p1x = (x,)
print (p1x)

刚刚产生了第一个(而不是整个X值......

任何解决方案?

ADDENDUM PT 2

所以会发生这样的事情:

====init=====
Frames Per Second: 24.0
Source Width: 2048
Source Height: 778
Source Pixel Aspect Ratio: 1
Comp Pixel Aspect Ratio: 1
5
frame: 20
(0.793803,0.136326,0,0.5,0)
x: (, y: y0
x: (, y: y0
x: (, y: y0
x: (, y: y0
x: (, y: y0

当我输入

(point1, point2, point3, point4, point5) = points
print (point1)
#print (point2)
#print (point3)
#print (point4)
#print (point5)

for point in points:
    x, y, *data = point
    print(str.format("x: {0}, y: y{1}", x, y))

file.close()

我不知道为什么会拉(来自(0.793803,0.136326,0,0.5,0)

我可以告诉你,程序认为如果我把x,y,z,w,s

我想要x:'('y:'0'z:'。'w:'7':'9' 我没有, 我想要: x:0.793803 y:0.136326 z:0 w:0.5 s:0

对于所有问题,我们非常感谢您的帮助

1 个答案:

答案 0 :(得分:3)

分数是元组,所以它很简单。

你可以先打开它们(p是一个点):

>>> x, y, *data = p
>>> x
0.793803
>>> y
0.136326
>>> data
[0, 0.5, 0]

或者你可以索引它们:

>>> p[0]
0.793803

或者你可以对字符串格式感到疯狂:

>>> str.format("x{0[0]} y{0[1]}", p)
'x0.793803 y0.136326'

好吧,也许不是最后一个。为了便于阅读,我先打开它们。


我在上下文中的例子:

for point in points:
    x, y, *data = point
    print(str.format("x: {0}, y: y{1}", x, y))

points是元组的“可迭代”,每个元组代表样条线上的一个点,捕获到变量point中。