我的配置:带有tableView的标签栏 - >点击行 - >的DetailView
我的问题:我用asihttp提出请求。到现在为止还挺好。我收到的答复如下:
name;tel;email
Hans Mustermann;0123/45678;info@yourdomain.com
Harry the second;98765/12345;my@email.com
目前我处理的响应如下:
NSArray *cusNameDataArray = nil;
cusNameDataArray = [[response componentsSeparatedByString:@"\n"]retain];
self.cusNameDataArray =[[NSMutableArray alloc] initWithArray:cusNameDataArray];
[cusNameDataArray release];
并在:
-(UITableViewCell *)tableView:(UITableView *)cusTableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
static NSString *identifier = @"Cell";
UITableViewCell *cell = [self.cusTableView dequeueReusableCellWithIdentifier:identifier];
if(cell == nil)
//cell = [[[UITableViewCell alloc] initWithFrame:CGRectZero reuseIdentifier:identifier] autorelease];
cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:identifier] autorelease];
// Set up the cell...
cell.textLabel.font = [UIFont fontWithName:@"Verdana" size:12];
cell.textLabel.text = **here i want the name**;
cell.detailTextLabel.font = [UIFont fontWithName:@"Verdana" size:10];
cell.detailTextLabel.text = *here i want the email and tel;
return cell;
}
您可以看到我只想在cell.textLabel.text
和cell.detailTextLabel.text
中使用电子邮件和电话
有人可以帮我一个例子吗?我浪费了很多时间来解决这个问题,但没找到任何东西
thx for your parser。我现在这样做但没有机会。
tableview
的单元格为空 - > cell.textlabel.text
和cell.detailtextlabel.text
我犯了一个愚蠢的错误吗?
- (void)viewDidLoad
{
[super viewDidLoad];
self.title = NSLocalizedString(@"Customers", @"My Customers");
NSURL *url = [NSURL URLWithString:@"http://www.yourdomain.com/some.php?do=yes"];
ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];
[request startSynchronous];
NSError *error = [request error];
if (!error) {
NSString *response = [request responseString];
NSLog(@"%@", response);
NSArray *cusDataArray = nil;
cusDataArray = [[response componentsSeparatedByString:@"\n"]retain];
// Allocate my customer array
self.cusDataArray =[[NSMutableArray alloc] init];
for (int i=0; i<[cusTempArray count]; i++)
{
NSString *cusLine = [cusTempArray objectAtIndex:i];
NSArray *cusComponents = [cusLine componentsSeparatedByString:@";"];
// cusComponents now contains 3 entries - name, number, e-mail. Add this to your customer data array
[self.cusDataArray addObject:cusComponents];
}
}
[cusDataArray release];
}
-(UITableViewCell *)tableView:(UITableView *)cusTableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
static NSString *identifier = @"Cell";
UITableViewCell *cell = [self.cusTableView dequeueReusableCellWithIdentifier:identifier];
if(cell == nil)
//cell = [[[UITableViewCell alloc] initWithFrame:CGRectZero reuseIdentifier:identifier] autorelease];
cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:identifier] autorelease];
// Iterate over ever line and break it up into its components
for (int i=0; i<[cusTempArray count]; i++)
{
NSString *cusLine = [cusTempArray objectAtIndex:i];
NSArray *cusComponents = [cusLine componentsSeparatedByString:@";"];
// cusComponents now contains 3 entries - name, number, e-mail. Add this to your customer data array
[self.cusDataArray addObject:cusComponents];
}
//Set up the cell...
cell.textLabel.font = [UIFont fontWithName:@"Verdana" size:12];
NSArray *customerData = [self.cusDataArray objectAtIndex:0];
NSString *customerName = [customerData objectAtIndex:0];
NSString *customerPhone = [customerData objectAtIndex:1];
cell.textLabel.text = customerName;
cell.detailTextLabel.font = [UIFont fontWithName:@"Verdana" size:10];
cell.detailTextLabel.text = [self.cusDataArray objectAtIndex:1];
return cell;
}
答案 0 :(得分:0)
我编写了一个可以处理此问题的CSV库,即使您的数据不是csv:
https://github.com/davedelong/CHCSVParser
在您的情况下,由于您需要指定自定义分隔符,您可以执行以下操作:
NSString *data = @"name;tel;email\nHans Mustermann;0123/45678;info@yourdomain.com\nHarry the second;98765/12345;my@email.com";
NSError *error = nil;
NSArray *split = [[NSArray alloc] initWithContentsOfCSVString:data encoding:NSUTF8StringEncoding delimiter:@";" error:&error];
NSLog(@"%@", split);
[split release];
当我运行它时,它会记录:
(
(
name,
tel,
email
),
(
"Hans Mustermann",
"0123/45678",
"info@yourdomain.com"
),
(
"Harry the second",
"98765/12345",
"my@email.com"
)
)