我在HTML5中有一个使用websql数据库的移动应用程序。我有一个data.js文件，其中包含一系列用于与数据库进行各种CRUD作业的函数。在我接通这个功能之前，我从未遇到过这个问题。基本上，该应用程序用于为商人创建报价，我正在编写的函数是获取引用和引用行，将它们转换为JSON对象并将它们转换为Web应用程序。
由于某些原因，我的db.transaction没有被执行。你能帮我搞清楚为什么吗？ db存在，因为其他函数正在调用这个确切的SQL。但它对他们有用而不是这个：
function syncQuote(){
var quote_id = localStorage["quote_id"];
var header = new Array(); // holds id, created, appointment_id
db = openDatabase("Quote", "0.1", "A collection of quotes.", 200000);
if(!db){
console.log('Failed to connect to database.');
}
console.log('Getting quote header data.');
db.transaction(
function(tx) {
tx.executeSql("SELECT * FROM quote_header WHERE id = ?", [quote_id],
function(tx, results) {
var len = results.rows.length;
for(var i=0; i< len; i++){
alert('booyah!');
header['quote_id'] = results.rows.item(i).id;
header['appointment_id'] = results.rows.item(i).appointment_id;
header['created'] = results.rows.item(i).created;
}
});
},
function(tx, error){
console.log(error.message);
}
);
// now get all quote lines for this quote
var lines = new Array();
console.log('getting quote lines');
db.transaction(
function(tx) {
tx.executeSql("SELECT DISTINCT areas.label as area, features.label as feature, products.label as product, hours, price, colour FROM quote_line JOIN areas ON quote_line.area_id = areas.area_id JOIN features ON quote_line.feature_id = features.feature_id JOIN products ON quote_line.product_id = products.product_id WHERE quote_line.quote_id = ?", [quote_id],
function(tx, results) {
len = results.rows.length;
for(var i=0; i< len; i++){
var area= results.rows.item(i).area;
var feature= results.rows.item(i).feature;
var product= results.rows.item(i).product;
var hours= results.rows.item(i).hours;
var price= results.rows.item(i).price;
var colour= results.rows.item(i).colour;
lines[i] = new Array(6);
lines[i][0] = area;
lines[i][1] = feature;
lines[i][2] = product;
lines[i][3] = hours;
lines[i][4] = price;
lines[i][5] = colour;
}
},
function(tx, error){
console.log(error.message);
}
);
}
);
var data = new Array(2);
data[0] = JSON.stringify(header);
data[1] = JSON.stringify(lines);
alert(data[0]);
alert(data[1]);
// post data to web app
var url = "http://*****.com/import_quote";
$.ajax({
type: 'POST',
url: url,
data: data,
success: quote_sync_success,
dataType: 'JSON'
});
}
我有成功和失败的回调，但都没有响应。
这也是我第一次从JS应用程序发布JSON，所以请随意发表评论。
谢谢，
比利
答案 0 :(得分：1)
复制此编辑的代码并查看其是否有效
function syncQuote(){
var quote_id = localStorage["quote_id"];
var header = new Array(); // holds id, created, appointment_id
db = openDatabase("Quote", "0.1", "A collection of quotes.", 200000);
if(!db){
console.log('Failed to connect to database.');
}
console.log('Getting quote header data.');
db.transaction(
function(tx) {
// CORRECTION 1: THE ? IS MEANT TO BE IN A BRACKET
tx.executeSql("SELECT * FROM quote_header WHERE id = (?)", [quote_id],
function(tx, results) {
var len = results.rows.length;
for(var i=0; i< len; i++){
alert('booyah!');
header['quote_id'] = results.rows.item(i).id;
header['appointment_id'] = results.rows.item(i).appointment_id;
header['created'] = results.rows.item(i).created;
}
});
},
function(tx, error){
console.log(error.message);
},
//CORRECTION 2
//THERE IS MEANT TO BE A SUCCESS CALL BACK FUNCTION HERE
function(){
console.log( 'Query Completed' )
}
);
// now get all quote lines for this quote
var lines = new Array();
console.log('getting quote lines');
db.transaction(
function(tx) {
// CORRECTION 3: WRONG CALL METHOD AND NONE-USE OF BRACKETS and QOUTES
tx.executeSql("SELECT DISTINCT areas.label as area, features.label as feature, products.label as product, hours, price, colour FROM quote_line JOIN areas ON quote_line.area_id = 'areas.area_id' JOIN features ON quote_line.feature_id = 'features.feature_id' JOIN products ON quote_line.product_id = 'products.product_id' WHERE quote_line.quote_id = (?)", [quote_id],
function(tx, results) {
len = results.rows.length;
for(var i=0; i< len; i++){
var area= results.rows.item(i).area;
var feature= results.rows.item(i).feature;
var product= results.rows.item(i).product;
var hours= results.rows.item(i).hours;
var price= results.rows.item(i).price;
var colour= results.rows.item(i).colour;
lines[i] = new Array(6);
lines[i][0] = area;
lines[i][1] = feature;
lines[i][2] = product;
lines[i][3] = hours;
lines[i][4] = price;
lines[i][5] = colour;
}
},
function(tx, error){
console.log(error.message);
}
);
}
);
var data = new Array(2);
data[0] = JSON.stringify(header);
data[1] = JSON.stringify(lines);
alert(data[0]);
alert(data[1]);
// post data to web app
var url = "http://*****.com/import_quote";
$.ajax({
type: 'POST',
url: url,
data: data,
success: quote_sync_success,
dataType: 'JSON'
});
}
答案 1 :(得分：0)
您是否尝试在成功回调开始时抛出console.log（）？如果len为0，那么你就不会得到任何输出