SQL更新错误与替换

Question

我看不出这个SQL有什么问题：

UPDATE Show
SET    EnterOnine = replace(EnterOnine, 'http://projects.example.co.uk', 'http://www.example.co.uk')
WHERE  EnterOnine LIKE '%http://projects.example.co.uk%'

当我将其输入PHPmyadmin时，我收到此错误：

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Show SET EnterOnine = replace(EnterOnine, 'http://projects.example.co.uk' at line 1

Answer 1

Show是mysql中的reserved word，使用反向标记进行转义。

UPDATE `Show` SET ...