Question

阅读这个问题Merge and group by several arrays我得到了以下想法：当使用多级数组，可能重复键时，有一个函数可以迭代这样的数组，因为它是平的，如

foreach(flatten($deepArray) as $key => $val)....

如何撰写flatten()的任何想法？有没有标准的解决方案？

（请注意，由于重复键，flatten()不能简单地返回新数组。）

Answer 1

RecursiveArrayIterator

的使用示例

$array = array( 
    0 => 'a', 
    1 => array('subA','subB',array(0 => 'subsubA', 1 => 'subsubB', 2 => array(0 => 'deepA', 1 => 'deepB'))), 
    2 => 'b', 
    3 => array('subA','subB','subC'), 
    4 => 'c' 
);

foreach (return new RecursiveIteratorIterator(new RecursiveArrayIterator($array))
         as $key => $val) {

    printf(
        '%s: %s' . "\n",
        $key, $val
    );
}

/* Output:
0: a
0: subA
1: subB
0: subsubA
1: subsubB
0: deepA
1: deepB
2: b
0: subA
1: subB
2: subC
4: c
*/

扩展RecursiveIteratorIterator以返回当前的密钥堆栈

class MyRecursiveIteratorIterator extends RecursiveIteratorIterator
{
  public function key() {
    return json_encode($this->getKeyStack());
  }

  public function getKeyStack() {
    $result = array();
    for ($depth = 0, $lim = $this->getDepth(); $depth < $lim; $depth += 1) {
      $result[] = $this->getSubIterator($depth)->key();
    }
    $result[] = parent::key();
    return $result;
  }
}

foreach ($it = new MyRecursiveIteratorIterator(new RecursiveArrayIterator($array))
         as $key => $val) {

  printf('%s (%s): %s' . "\n", implode('.', $it->getKeyStack()), $key, $val);
}

/* Output:
0 ([0]): a
1.0 ([1,0]): subA
1.1 ([1,1]): subB
1.2.0 ([1,2,0]): subsubA
1.2.1 ([1,2,1]): subsubB
1.2.2.0 ([1,2,2,0]): deepA
1.2.2.1 ([1,2,2,1]): deepB
2 ([2]): b
3.0 ([3,0]): subA
3.1 ([3,1]): subB
3.2 ([3,2]): subC
4 ([4]): c
*/

又一个版本，这次没有使用RecursiveArrayIterator：

function flatten(array $array = array(), $keyStack = array(), $result = array()) {
  foreach ($array as $key => $value) {
    $keyStack[] = $key;

    if (is_array($value)) {
      $result = flatten($value, $keyStack, $result);
    }
    else {
      $result[] = array(
        'keys' => $keyStack,
        'value' => $value
      );
    }

    array_pop($keyStack);
  }

  return $result;
}

foreach (flatten($array) as $element) {
  printf(
    '%s: %s (depth: %s)' . "\n",
    implode('.', $element['keys']),
    $element['value'],
    sizeof($element['keys'])
  );
}

/*
0: a (depth: 1)
1.0: subA (depth: 2)
1.1: subB (depth: 2)
1.2.0: subsubA (depth: 3)
1.2.1: subsubB (depth: 3)
1.2.2.0: deepA (depth: 4)
1.2.2.1: deepB (depth: 4)
2: b (depth: 1)
3.0: subA (depth: 2)
3.1: subB (depth: 2)
3.2: subC (depth: 2)
4: c (depth: 1)
*/

Answer 2

您还可以编写一个简单的遍历函数：

function flatten($node, $fn, $keys = array()) {
    if (! is_array($node)) {
        $fn($node, $keys);
    } else {
        foreach ($node as $k => $v) {
            $new_keys   = $keys;
            $new_keys[] = $k;
            flatten($v, $fn, $new_keys);
        }
    }
}

$array = array( 
    0 => 'a', 
    1 => array('subA','subB',array(0 => 'subsubA', 1 => 'subsubB', 2 => array(0 => 'deepA', 1 => 'deepB'))), 
    2 => 'b', 
    3 => array('subA','subB','subC'), 
    4 => 'c' 
);
// will output: a subA subB subsubA subsubB deepA deepB b subA subB subC c 
flatten($array, function($v, $k) {
    echo $v . ' ';
});

如果您不希望每次使用其他函数作为参数调用它，我还编写了一个将返回数组的适配器：

function flatten_array($node) {
    $acc = array();
    flatten($node, function($node, $keys) use (&$acc) {
        $acc[implode('.', $keys)] = $node;
    });
    return $acc;
}

// will spit out the same output as that in Yoshi's answer:
foreach (flatten_array($array) as $k => $v) {
    echo $k .' => ' . $v . "\n";
}

注意：

array_walk_recursive不能使用/不是同一个东西，因为它跳过持有数组的键
我用匿名函数编写了我的例子;如果您的PHP不够新，则必须为这些函数命名并使用call_user_func调用它们。

透明地展平阵列

2 个答案: