Question

我正在尝试使用HttpWebRequest通过POST将数据发送到REST Web服务，然后使用额外的HttpWebRequest跟进，以便在处理后下载响应。

POST正在将二进制数据发送到Web服务，如下所示：

HttpWebRequest uploadRequest = (HttpWebRequest)WebRequest.Create(baseAddress + uploadURIRequest);
uploadRequest.Timeout = Timeout.Infinite;
uploadRequest.ReadWriteTimeout = Timeout.Infinite;
uploadRequest.Method = "POST";
uploadRequest.ContentLength = fileInfo.Length;
uploadRequest.ContentType = "application/octet-stream";

using (Stream writeStream = uploadRequest.GetRequestStream())
{
    using (FileStream readStream = new FileStream(fileStreamFileName, FileMode.Open, FileAccess.Read))
    {
        byte[] data= new byte[readStream.Length];
        int bytesRead = readStream.Read(data, 0, (int)readStream.Length);
        writeStream.Write(data, 0, bytesRead);

        readStream.Close();
    }
    writeStream.Close();
}

然后，下一个请求是告诉Web服务处理服务器上的数据并返回状态响应。

HttpWebRequest processRequest = (HttpWebRequest)WebRequest.Create(baseAddress + processURIRequest);
processRequest.Timeout = 10000;
processRequest.ReadWriteTimeout = 10000;
processRequest.ContentType = "GET";

HttpWebResponse processRequestResponse = (HttpWebResponse)processRequest.GetResponse();

using (Stream processRequestResponseStream = processRequestResponse.GetResponseStream())
{
    //Do stuff...

}

当我更改内容类型时，它适用于XML数据。但是，当我如上所示保留二进制数据时，操作总是超时...即使我将超时增加到超过10秒。它正在进行的处理不应该花这么长时间才能返回。

当我调试时，它总是挂在GetResponse：

的行上

HttpWebResponse processRequestResponse = (HttpWebResponse)processRequest.GetResponse();

Answer 1

添加

HttpWebResponse uploadRequestResponse = (HttpWebResponse)uploadRequest.GetResponse();

写入流后，

解决了这个问题。

WebRequest GetResponse没有响应，操作超时

1 个答案: