我需要一个多线布局,它可以表现为水平线性布局,但是当没有足够的空间放置新的小部件时,它会扩展到下一行,就像文本中的单词一样。小部件将在运行时添加到那里,并应与wrap_content
一起使用。实际上,会有按钮。
是否有任何具有此类行为的小部件?或者给出一个关于如何自己编写这种布局的建议。
最后看起来应该是这样的:
答案 0 :(得分:23)
检查评论:这将完成工作
/*
* Copyright 2011 Sherif
*/
private void populateText(LinearLayout ll, View[] views , Context mContext) {
Display display = getWindowManager().getDefaultDisplay();
ll.removeAllViews();
int maxWidth = display.getWidth() - 20;
LinearLayout.LayoutParams params;
LinearLayout newLL = new LinearLayout(mContext);
newLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT,
LayoutParams.WRAP_CONTENT));
newLL.setGravity(Gravity.LEFT);
newLL.setOrientation(LinearLayout.HORIZONTAL);
int widthSoFar = 0;
for (int i = 0 ; i < views.length ; i++ ){
LinearLayout LL = new LinearLayout(mContext);
LL.setOrientation(LinearLayout.HORIZONTAL);
LL.setGravity(Gravity.CENTER_HORIZONTAL|Gravity.BOTTOM);
LL.setLayoutParams(new ListView.LayoutParams(
LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
//my old code
//TV = new TextView(mContext);
//TV.setText(textArray[i]);
//TV.setTextSize(size); <<<< SET TEXT SIZE
//TV.measure(0, 0);
views[i].measure(0,0);
params = new LinearLayout.LayoutParams(views[i].getMeasuredWidth(),
LayoutParams.WRAP_CONTENT);
//params.setMargins(5, 0, 5, 0); // YOU CAN USE THIS
//LL.addView(TV, params);
LL.addView(views[i], params);
LL.measure(0, 0);
widthSoFar += views[i].getMeasuredWidth();// YOU MAY NEED TO ADD THE MARGINS
if (widthSoFar >= maxWidth) {
ll.addView(newLL);
newLL = new LinearLayout(mContext);
newLL.setLayoutParams(new LayoutParams(
LayoutParams.FILL_PARENT,
LayoutParams.WRAP_CONTENT));
newLL.setOrientation(LinearLayout.HORIZONTAL);
newLL.setGravity(Gravity.LEFT);
params = new LinearLayout.LayoutParams(LL
.getMeasuredWidth(), LL.getMeasuredHeight());
newLL.addView(LL, params);
widthSoFar = LL.getMeasuredWidth();
} else {
newLL.addView(LL);
}
}
ll.addView(newLL);
}
答案 1 :(得分:18)
/**
* Copyright 2011 Sherif
* Updated by Karim Varela to handle LinearLayouts with other views on either side.
* @param linearLayout
* @param views : The views to wrap within LinearLayout
* @param context
* @param extraView : An extra view that may be to the right or left of your LinearLayout.
* @author Karim Varela
**/
private void populateViews(LinearLayout linearLayout, View[] views, Context context, View extraView)
{
extraView.measure(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
// kv : May need to replace 'getSherlockActivity()' with 'this' or 'getActivity()'
Display display = getSherlockActivity().getWindowManager().getDefaultDisplay();
linearLayout.removeAllViews();
int maxWidth = display.getWidth() - extraView.getMeasuredWidth() - 20;
linearLayout.setOrientation(LinearLayout.VERTICAL);
LinearLayout.LayoutParams params;
LinearLayout newLL = new LinearLayout(context);
newLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
newLL.setGravity(Gravity.LEFT);
newLL.setOrientation(LinearLayout.HORIZONTAL);
int widthSoFar = 0;
for (int i = 0; i < views.length; i++)
{
LinearLayout LL = new LinearLayout(context);
LL.setOrientation(LinearLayout.HORIZONTAL);
LL.setGravity(Gravity.CENTER_HORIZONTAL | Gravity.BOTTOM);
LL.setLayoutParams(new ListView.LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
views[i].measure(0, 0);
params = new LinearLayout.LayoutParams(views[i].getMeasuredWidth(), LayoutParams.WRAP_CONTENT);
params.setMargins(5, 0, 5, 0);
LL.addView(views[i], params);
LL.measure(0, 0);
widthSoFar += views[i].getMeasuredWidth();
if (widthSoFar >= maxWidth)
{
linearLayout.addView(newLL);
newLL = new LinearLayout(context);
newLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
newLL.setOrientation(LinearLayout.HORIZONTAL);
newLL.setGravity(Gravity.LEFT);
params = new LinearLayout.LayoutParams(LL.getMeasuredWidth(), LL.getMeasuredHeight());
newLL.addView(LL, params);
widthSoFar = LL.getMeasuredWidth();
}
else
{
newLL.addView(LL);
}
}
linearLayout.addView(newLL);
}
答案 2 :(得分:2)
您现在可以使用Google的Flexbox布局(https://github.com/google/flexbox-layout)轻松解决此问题。