Question

我有formview控件。在formview控件里面他们是一个gridview。在gridview中我有FooterTemplate（在footertemplate我有文本框控件来添加文本）来添加文本。为了找到那个控件，我编写了如下代码：

 GridView mygridview = (GridView)FVAddCustomer.FindControl("mygridview");
TextBox txtFName1 = (TextBox)mygridview.FooterRow.FindControl("txtFName1");

这是正确的还是其他方式？因为当我找到文本框值然后它变为空？请帮我？

  <asp:GridView ID="mygridview" runat="server" AutoGenerateColumns="False" ShowFooter="True" BackColor="White" BorderColor="#336666" BorderWidth="3px" CellPadding="4" GridLines="Horizontal" BorderStyle="Double" Width="100%" OnRowEditing="mygridview_RowEditing" OnRowCancelingEdit="mygridview_RowCancelingEdit" OnRowUpdating="mygridview_RowUpdating" Visible="false">
       <FooterStyle BackColor="White" ForeColor="#333333" />
       <PagerStyle BackColor="#336666" ForeColor="White" HorizontalAlign="Center" />
       <SelectedRowStyle BackColor="#339966" ForeColor="White" Font-Bold="True" />
       <HeaderStyle BackColor="#336666" Font-Bold="True" ForeColor="White" />
       <Columns>
          <asp:TemplateField HeaderText="First Name">
             <ItemTemplate>
                 <asp:Label ID="lblFName1" runat="server" Text='<%#Eval("FirstName")%>'></asp:Label>
             </ItemTemplate>
             <EditItemTemplate>
                  <asp:TextBox ID="txtFName1Edit" runat="server" Width="90px"></asp:TextBox>
            </EditItemTemplate>
            <FooterTemplate>
               <asp:TextBox ID="txtFName1" runat="server" Width="90px"></asp:TextBox>
            </FooterTemplate>
        </asp:TemplateField>
        <asp:TemplateField HeaderText="Edit">
            <ItemTemplate>
               <asp:LinkButton ID="lnkEdit" runat="server" Text="Edit" CommandName="Edit" CausesValidation="false" OnClick="lnkEdit_Click"></asp:LinkButton>
            </ItemTemplate>
            <EditItemTemplate>
              <asp:LinkButton ID="lnkUpdate" runat="server" Text="Update" CommandName="Update"></asp:LinkButton>
              <asp:LinkButton ID="lnkCancel" runat="server" Text="cancel" CommandName="Cancel"></asp:LinkButton>
            </EditItemTemplate>
            <FooterTemplate>
                <asp:LinkButton ID="lnkAdd" runat="server" Text="Add" CommandName="Add" Width="90px" OnClick="lnkAdd_Click"></asp:LinkButton>
            </FooterTemplate>
         </asp:TemplateField>

谢谢。 Asp.net C＃

Answer 1

来自评论：

你以前调用过FormView.DataBind / GridView.DataBind吗？

还要记住FormView有3种不同的FormViewModes。如果它当前处于编辑模式并且GridView位于ReadOnly ItemTemplate中，则您无法访问它。

尝试使用LinkButton的click-event处理程序获取TextBox：

private void lnkadd_Click(object sender, System.EventArgs e)
{
    var footer = (GridViewRow)((WebControl)sender).NamingContainer;
    var txtFName1 = (TextBox)footer.FindControl("footer");
}

编辑：如果这不起作用，您可以尝试处理GridView's RowCommand：

protected void mygridview_RowCommand(object sender, System.Web.UI.WebControls.GridViewCommandEventArgs e)
{
    if (e.CommandName == "Add") {
        var txtFName1 = (TextBox)((GridView)sender).FooterRow.FindControl("txtFName1");
    }
}

EDIT2：

只有在!IsPostBack时才应将GridView绑定到它的DataSource。最好的地方是在FormView的DataBound事件中：

protected void FormView1_DataBound(object sender, System.EventArgs e)
{
    switch (FormView1.CurrentMode) {
        case FormViewMode.Insert:
            var mygridview = (GridView)((FormView)sender).FindControl("mygridview");
            //Bind your GridView here'
            break;
    }
}

通过这种方式，您可以确保在FormView获取数据绑定时GridView将自动反弹。如果FormView将其模式更改为Insert，即使数据源为DataBind，您也必须null！

Answer 2

我发现我的网格只应在pageLoad事件中出现(!IsPostback)时填充。像这样：

protected void Page_Load(object sender, EventArgs e)
{
    if (!IsPostBack)
    {
        FillGrid();
    }
}

然后我执行了成功的插入操作

protected void CustomerGridview_RowCommand(object sender, GridViewCommandEventArgs e)
{
        bool flag = false;
        if (e.CommandName.Equals("Insert")) 
        {
            TextBox txtNewName = (TextBox)CustomerGridview.FooterRow.FindControl("txtNewName");                
            DropDownList ddlNewGender = (DropDownList)CustomerGridview.FooterRow.FindControl("ddlNewGender");
            DropDownList ddlNewType = (DropDownList)CustomerGridview.FooterRow.FindControl("cmbNewType");
            CheckBox chkNewActive = (CheckBox)CustomerGridview.FooterRow.FindControl("chkNewActive");
            if (chkNewActive.Checked) flag = true;
            else
                flag = false;
            SqlConnection con = new SqlConnection(conection);
            con.Open();
            SqlCommand command = con.CreateCommand();
            SqlTransaction transaction;
            // Start a local transaction.
            transaction = con.BeginTransaction();
            // Must assign both transaction object and connection 
            // to Command object for a pending local transaction
            command.Connection = con;
            command.Transaction = transaction;

            try
            {
                command.CommandText = "Insert into Contact (Name,Sex,Type,IsActive) values('" + txtNewName.Text + "','" + ddlNewGender.SelectedValue.ToString() + "','" + ddlNewType.SelectedValue.ToString() + "','" + flag + "')";
                command.ExecuteNonQuery();
                transaction.Commit();
                Message.Text = "Record has been saved!!";
            }
            catch (Exception ex)
            {
                Message.Text = "Error Occured!!";
                try
                {
                    transaction.Rollback();
                }
                catch(Exception ex2)
                {
                    Message.Text = "Transaction RollBack!";
                }
            }   
            FillGrid();
        }
    }

关于在asp.net中的formview里面找到gridview里面的页脚控件

2 个答案: