Question

继我之前的问题。现在我有两个不同的查询。第一个查询返回5092的结果，第二个查询返回1885的结果，最多为6977.我想将它们组合成一个查询以返回6977的结果。如何使一个查询计算条件评估的数量活跃，逾期超过14天且为空（算作逾期）？提前致谢。

select count (*)
from task_conditionassessment t
    inner join taskitems_conditionassessment ti on
        t.task_conditionassessmentguid=ti.task_conditionassessmentguid  
    inner join conditionassessmentassignmentitem c on
        ti.taskitems_conditionassessmentid=c.taskitems_conditionassessmentid
where datediff(dd,c.conditionassessmentdate,t.nextduedate)>14 and t.isactive=1


select t.taskname,t.nextduedate,c.conditionassessmentdate
from task_conditionassessment t
    inner join taskitems_conditionassessment ti on
        t.task_conditionassessmentguid=ti.task_conditionassessmentguid
    inner join conditionassessmentassignmentitem c on
        ti.taskitems_conditionassessmentid=c.taskitems_conditionassessmentid
where c.conditionassessmentdate IS NULL and t.isactive=1

Answer 1

如果您只想要符合任何一组条件的记录数，请在or子句中使用where：

select count (*)
from task_conditionassessment t
inner join taskitems_conditionassessment ti on
    t.task_conditionassessmentguid=ti.task_conditionassessmentguid  
inner join conditionassessmentassignmentitem c on
    ti.taskitems_conditionassessmentid=c.taskitems_conditionassessmentid
where (c.conditionassessmentdate IS NULL or
       datediff(dd,c.conditionassessmentdate,t.nextduedate)>14) and
      t.isactive=1

Answer 2

如果我理解正确，只需OR两个条件：

select count (*)
from task_conditionassessment t
    inner join taskitems_conditionassessment ti on t.task_conditionassessmentguid=ti.task_conditionassessmentguid
    inner join conditionassessmentassignmentitem c on ti.taskitems_conditionassessmentid=c.taskitems_conditionassessmentid
where (datediff(dd,c.conditionassessmentdate,t.nextduedate)>14
        or c.conditionassessmentdate IS NULL)
    and t.isactive=1

计算DIFFDATE超过指定值 - 步骤2

2 个答案: