Question

我有一个名为student的表，有两列：

JoinDate DATE
EmployeeName STRING

表的内容如下：

EmployeeName    | JoinDate
----------------+-----------------
jaison          | 1-jan-2008
robin           | 2-feb-2008
binoy           | 3-mar-2008
rahul           | 4-feb-2008

我希望根据此表准备以下输出：包含名称为jan，feb，mar，april的4列的表。在这几个月的每个月之下，计数为1,2,1,0。这些计数表示当月加入的员工人数（1月1日员工，2月2日员工，3月1日员工，4月0日员工）

你能给我所需的SQL查询吗？

Answer 1

这会有效，任何人都知道吗？

SELECT Sum([1]) AS Jan, Sum([2]) AS Feb, Sum([3]) AS Mar, Sum([4]) as Apr,
       Sum([5]) as May, Sum([6]) as Jun, Sum([7]) as Jul, Sum([8]) as Aug,
       Sum([9]) as Sep, Sum([10]) as Oct, Sum([11]) as Nov, Sum([12]) as Dec
FROM (SELECT Month(Join_Date) as Mon FROM student) ps
PIVOT
    (Count(Mon) FOR Mon IN 
        ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12])
    ) AS pvt
GROUP BY [1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12]

Answer 2

以下查询将为您提供两列（月份和总计）的结果集，其中月份是月份名称，总数是该月份加入的人数：

SELECT MONTHNAME(`join_date`) AS `month`, COUNT(*) AS `total` GROUP BY MONTHNAME(`join_date`);

Answer 3

这也可行

Create table [sample] (Employeename varchar(50), join_date smalldatetime)
insert into [sample] values('Ganesh','01/26/2008')
insert into [sample] values('Ramesh','02/26/2008')
insert into [sample] values('Dinesh','03/26/2008')
insert into [sample] values('Suresh','01/26/2008')

Select * from [sample]

SELECT 'Students Admission by Monthwise' ,[1] AS january,[2] AS february,[3] AS March,[4] AS April
FROM( 
        SELECT  Employeename,
                Month(join_date) monthname 
        FROM    [sample]
    ) A
PIVOT
(
    COUNT(Employeename)
    FOR monthname in
        ([1],[2],[3],[4])
) AS PVT

用于生成给定数据的SQL查询

3 个答案: